Digital Electronics - Flip-Flops - Discussion
Discussion Forum : Flip-Flops - General Questions (Q.No. 1)
1.
Determine the output frequency for a frequency division circuit that contains 12 flip-flops with an input clock frequency of 20.48 MHz.
Discussion:
35 comments Page 4 of 4.
Vbnbh said:
9 years ago
Mod no = Fin/Fout -->(1)
Mod no. = 2^N -->(2) Where N is the no. of flip flop
Hence Mod no = 2^(12)= Fout = 20.48 / [2^(12)].
Mod no. = 2^N -->(2) Where N is the no. of flip flop
Hence Mod no = 2^(12)= Fout = 20.48 / [2^(12)].
(2)
Yaswant said:
8 years ago
According to me, it's 20.48M/2^12.
(3)
PARASHUUUUU said:
7 years ago
12 flip-flop =2^12 =4096.
Input clock frequency of 20.48 MHz.
F=I/P CLOCK FREQUENCY/2^N.
F=(20.48X10^6)/2^12 =5KHZ.
Input clock frequency of 20.48 MHz.
F=I/P CLOCK FREQUENCY/2^N.
F=(20.48X10^6)/2^12 =5KHZ.
(6)
Jasso said:
3 years ago
The Output Clock frequency = 20480000/4096 = 5000 i.e., 5 kHz.
(1)
Ramakrishna said:
2 years ago
Output frequency = Input Freq./2^N.
Here, N is a number of flip-flops.
Here, N is a number of flip-flops.
(7)
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