Digital Electronics - Flip-Flops - Discussion

Discussion Forum : Flip-Flops - General Questions (Q.No. 1)
1.
Determine the output frequency for a frequency division circuit that contains 12 flip-flops with an input clock frequency of 20.48 MHz.
10.24 kHz
5 kHz
30.24 kHz
15 kHz
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
35 comments Page 1 of 4.

Ramakrishna said:   2 years ago
Output frequency = Input Freq./2^N.

Here, N is a number of flip-flops.
(7)

PARASHUUUUU said:   7 years ago
12 flip-flop =2^12 =4096.

Input clock frequency of 20.48 MHz.

F=I/P CLOCK FREQUENCY/2^N.
F=(20.48X10^6)/2^12 =5KHZ.
(6)

Yaswant said:   8 years ago
According to me, it's 20.48M/2^12.
(3)

Vbnbh said:   9 years ago
Mod no = Fin/Fout -->(1)
Mod no. = 2^N -->(2) Where N is the no. of flip flop

Hence Mod no = 2^(12)= Fout = 20.48 / [2^(12)].
(2)

Jasso said:   3 years ago
The Output Clock frequency = 20480000/4096 = 5000 i.e., 5 kHz.
(1)

Zoro said:   1 decade ago
Input frequency/no.of sequence of count.

DSingh said:   1 decade ago
The output frequency after each of the flip flop divided by 2.
So after 12 stages the clock frequency becomes

= 20.48*10^6/2^12=~5 KHz.

Hence option B is correct.

Devaraj said:   1 decade ago
1FF are used divide the clock frequency by 2.

12ff divide the frequency by 2^(12).

Given i/p frequency = 20.48MHZ.

Then o/p frequency = (20.48*10^6)/(2^12).

= 5 khz.

Deepika said:   1 decade ago
As the input given, we have to find the output frequency. The formula is:

Output frequency = input frequency/2^n.

Where n is no.of flip-flops.

Khitab Oza said:   1 decade ago
Output frequency = input frequency/n^12.

Where n=2 for divide-by-2 divider normally it takes n=2.


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