Digital Electronics - Flip-Flops - Discussion
Discussion Forum : Flip-Flops - General Questions (Q.No. 1)
1.
Determine the output frequency for a frequency division circuit that contains 12 flip-flops with an input clock frequency of 20.48 MHz.
Discussion:
35 comments Page 3 of 4.
Newbie_ynv said:
1 decade ago
On what basis its 2^12 ?
Gagan said:
1 decade ago
Please tell the formula.
Kowsalya said:
1 decade ago
On what basis 20.48*10^6?
Divyanshu said:
1 decade ago
@Kowsalya
20.48 MHz = 20.48*10^6 Hz
20.48 MHz = 20.48*10^6 Hz
Manimegala said:
1 decade ago
Output frequency = Input Freq./2^N.
Here N is no of filp-flops.
Here N is no of filp-flops.
Nisha said:
1 decade ago
@manimegala
Yes correct.
Yes correct.
Arunalex said:
1 decade ago
N=number of Flip Flop, Input Frequency in MHz so 10^6
Pratyusha said:
1 decade ago
12 flip flops = 2^12 = 4096.
=> 20.48*10^6=20480000.
20480000/4096 = 5000 i.e., 5 kHz.
=> 20.48*10^6=20480000.
20480000/4096 = 5000 i.e., 5 kHz.
Mahi said:
1 decade ago
Formula of @Manimegala is correct
Nandan Roy said:
1 decade ago
If N flip flops are connected, then input frequency is divided by 2^n.
So in this problem
20.48 * 10^6 / 2^12 = 5000Hz.
So in this problem
20.48 * 10^6 / 2^12 = 5000Hz.
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