Digital Electronics - Combinational Logic Circuits - Discussion

Discussion Forum : Combinational Logic Circuits - General Questions (Q.No. 1)
How many 3-line-to-8-line decoders are required for a 1-of-32 decoder?
Answer: Option
No answer description is available. Let's discuss.
14 comments Page 1 of 2.

Reshma said:   2 years ago
32/8=4 is correct,

If enable input 4 decoders needed means, 4 enable inputs are needed right?

Adeena said:   4 years ago
How can 2 to 4 line decoder be used in this? Can you tell by the circuit diagram?

Suren said:   4 years ago
5 input lines is the correct answer.

Ann said:   5 years ago
What is a demultiplexer?

Rajashekar said:   6 years ago
(32÷8) + (4÷8) =4.5.

So, the answer is 4.

Keerthi said:   6 years ago
Your explanation is simple and clear to understand @Ayyappa.

Rajaram said:   6 years ago
Decoder can be used as demultiplexer also, so 1x32 demux is similar to 5x32 decoder. Here 3x8 decoders (4x8 =32 outputs) input is single line. So 2 input line is used in chip selection one of 4 chip.

MVP said:   7 years ago
Decoders having 2^m outputs and m inputs w.r.t this to obtain 32(2^5) output lines we need 5input lines.

How come you can make 1-32 decoder?

Amareswari said:   7 years ago
We need one 2 to 4 decoder and four 3 to 8 decoders to implement 5 to 32 decoder.

Ravi said:   7 years ago
Explain in the form of diagram eg. decoder.

Post your comments here:

Your comments will be displayed after verification.