Digital Electronics - Combinational Logic Circuits - Discussion
Discussion Forum : Combinational Logic Circuits - General Questions (Q.No. 1)
1.
How many 3-line-to-8-line decoders are required for a 1-of-32 decoder?
Discussion:
14 comments Page 2 of 2.
AJAY KUMAR said:
9 years ago
I think 1 to 32 means 5 by 32.
32/8 = 4 decoders sufficient but what about inputs?
Now inputs are 12 (4 decoders * inputs 3) , so again we need 2 decoders to complete the circuit.
32/8 = 4 decoders sufficient but what about inputs?
Now inputs are 12 (4 decoders * inputs 3) , so again we need 2 decoders to complete the circuit.
AYYAPPA said:
1 decade ago
Required outputs/given outputs == (32/8) = 4.
Ravi kumar sinha said:
1 decade ago
In order to have 32 output lines you need to have 4 3*8 decorder and for the input you can connect enable and enable bar to four different different decorder so that we can different configuration for 1 input lines.
Muhdin Abdo said:
1 decade ago
The 3-input data lines used as common lines for the 4-decoder of 8-out puts. Thus, one could have a total of 4*8=32 out puts. Hence one needs 4 a 3-line-to-8-line decoders.
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