Digital Electronics - Combinational Logic Circuits - Discussion

Discussion Forum : Combinational Logic Circuits - General Questions (Q.No. 1)
1.
How many 3-line-to-8-line decoders are required for a 1-of-32 decoder?
1
2
4
8
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
14 comments Page 1 of 2.

Rajaram said:   8 years ago
Decoder can be used as demultiplexer also, so 1x32 demux is similar to 5x32 decoder. Here 3x8 decoders (4x8 =32 outputs) input is single line. So 2 input line is used in chip selection one of 4 chip.
(1)

Ann said:   7 years ago
What is a demultiplexer?
(1)

Adeena said:   6 years ago
How can 2 to 4 line decoder be used in this? Can you tell by the circuit diagram?
(1)

Reshma said:   3 years ago
32/8=4 is correct,

If enable input 4 decoders needed means, 4 enable inputs are needed right?
(1)

Muhdin Abdo said:   1 decade ago
The 3-input data lines used as common lines for the 4-decoder of 8-out puts. Thus, one could have a total of 4*8=32 out puts. Hence one needs 4 a 3-line-to-8-line decoders.

Ravi kumar sinha said:   1 decade ago
In order to have 32 output lines you need to have 4 3*8 decorder and for the input you can connect enable and enable bar to four different different decorder so that we can different configuration for 1 input lines.

AYYAPPA said:   1 decade ago
Required outputs/given outputs == (32/8) = 4.

AJAY KUMAR said:   9 years ago
I think 1 to 32 means 5 by 32.

32/8 = 4 decoders sufficient but what about inputs?

Now inputs are 12 (4 decoders * inputs 3) , so again we need 2 decoders to complete the circuit.

Ravi said:   9 years ago
Explain in the form of diagram eg. decoder.

Amareswari said:   9 years ago
We need one 2 to 4 decoder and four 3 to 8 decoders to implement 5 to 32 decoder.


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