Data Interpretation - Table Charts - Discussion
Discussion Forum : Table Charts - Table Chart 3 (Q.No. 1)
Directions to Solve
The following table gives the percentage of marks obtained by seven students in six different subjects in an examination.
The Numbers in the Brackets give the Maximum Marks in Each Subject.
| Student | Subject (Max. Marks) | |||||
| Maths | Chemistry | Physics | Geography | History | Computer Science | |
| (150) | (130) | (120) | (100) | (60) | (40) | |
| Ayush | 90 | 50 | 90 | 60 | 70 | 80 |
| Aman | 100 | 80 | 80 | 40 | 80 | 70 |
| Sajal | 90 | 60 | 70 | 70 | 90 | 70 |
| Rohit | 80 | 65 | 80 | 80 | 60 | 60 |
| Muskan | 80 | 65 | 85 | 95 | 50 | 90 |
| Tanvi | 70 | 75 | 65 | 85 | 40 | 60 |
| Tarun | 65 | 35 | 50 | 77 | 80 | 80 |
1.
What are the average marks obtained by all the seven students in Physics? (rounded off to two digit after decimal)
Answer: Option
Explanation:
Average marks obtained in Physics by all the seven students
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| + (80% of 120) + (85% of 120) + (65% of 120) + (50% of 120) ] | |||||
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| = 89.14. |
Discussion:
51 comments Page 4 of 6.
Rohit said:
8 years ago
80% of 120 is 96 not 90.
Mouni said:
8 years ago
Simple= 520/100*120=624.
You can try to first divisible get 0 or canceled and got multiply 12*52=624.
You can try to first divisible get 0 or canceled and got multiply 12*52=624.
Pavan W. said:
7 years ago
Easy way:-
((Total Marks)/(No. of Students))*(outoff marks).
i.e. (520/7)*120 = 89.14.
[520*120]/7 =86.14.
((Total Marks)/(No. of Students))*(outoff marks).
i.e. (520/7)*120 = 89.14.
[520*120]/7 =86.14.
Sushmitha reddy said:
7 years ago
I can't understand this problem. Can you explain cleary to me?
Bhanu said:
7 years ago
They have given in the question that percentage of marks so we are taking 520% of 120.
Rajat said:
7 years ago
As in question, we are having the percentage of marks not the marks of the subjects, therefore, we are doing.
[(90% of 120) + (80% of 120) + (70% of 120) + (80% of 120) + (85% of 120) + (65% of 120) + (50% of 120)]
Here,
1/7x [(90 + 80 + 70 + 80 + 85 + 65 + 50)% of 120].
we have taken the 120 as common and afterwards, we found our solution.
[(90% of 120) + (80% of 120) + (70% of 120) + (80% of 120) + (85% of 120) + (65% of 120) + (50% of 120)]
Here,
1/7x [(90 + 80 + 70 + 80 + 85 + 65 + 50)% of 120].
we have taken the 120 as common and afterwards, we found our solution.
Manojkumar.v said:
7 years ago
As per my solution;
First, l am calculating to the total % in physics 120% total marks 7.
(90+80+70+80+85+65+50)/7 * 120 = 520/7 * 120 = 74.3 * 120 = 89.16.
First, l am calculating to the total % in physics 120% total marks 7.
(90+80+70+80+85+65+50)/7 * 120 = 520/7 * 120 = 74.3 * 120 = 89.16.
(1)
Roopa said:
7 years ago
How we get 90%of 120 = 90?
(2)
XYZ said:
6 years ago
Questions should mention all the details.
(1)
Milan Pipaliya said:
5 years ago
In Computer Science Max Mark is 40, But Student Marks is given up to 90. How can we get 90 marks even Max mark is 40 only.
(1)
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