Data Interpretation - Table Charts - Discussion
Discussion Forum : Table Charts - Table Chart 3 (Q.No. 1)
Directions to Solve
The following table gives the percentage of marks obtained by seven students in six different subjects in an examination.
The Numbers in the Brackets give the Maximum Marks in Each Subject.
| Student | Subject (Max. Marks) | |||||
| Maths | Chemistry | Physics | Geography | History | Computer Science | |
| (150) | (130) | (120) | (100) | (60) | (40) | |
| Ayush | 90 | 50 | 90 | 60 | 70 | 80 |
| Aman | 100 | 80 | 80 | 40 | 80 | 70 |
| Sajal | 90 | 60 | 70 | 70 | 90 | 70 |
| Rohit | 80 | 65 | 80 | 80 | 60 | 60 |
| Muskan | 80 | 65 | 85 | 95 | 50 | 90 |
| Tanvi | 70 | 75 | 65 | 85 | 40 | 60 |
| Tarun | 65 | 35 | 50 | 77 | 80 | 80 |
1.
What are the average marks obtained by all the seven students in Physics? (rounded off to two digit after decimal)
Answer: Option
Explanation:
Average marks obtained in Physics by all the seven students
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| + (80% of 120) + (85% of 120) + (65% of 120) + (50% of 120) ] | |||||
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| = 89.14. |
Discussion:
54 comments Page 3 of 6.
Rajat said:
8 years ago
As in question, we are having the percentage of marks not the marks of the subjects, therefore, we are doing.
[(90% of 120) + (80% of 120) + (70% of 120) + (80% of 120) + (85% of 120) + (65% of 120) + (50% of 120)]
Here,
1/7x [(90 + 80 + 70 + 80 + 85 + 65 + 50)% of 120].
we have taken the 120 as common and afterwards, we found our solution.
[(90% of 120) + (80% of 120) + (70% of 120) + (80% of 120) + (85% of 120) + (65% of 120) + (50% of 120)]
Here,
1/7x [(90 + 80 + 70 + 80 + 85 + 65 + 50)% of 120].
we have taken the 120 as common and afterwards, we found our solution.
Bhanu said:
8 years ago
They have given in the question that percentage of marks so we are taking 520% of 120.
Sushmitha reddy said:
8 years ago
I can't understand this problem. Can you explain cleary to me?
Pavan W. said:
8 years ago
Easy way:-
((Total Marks)/(No. of Students))*(outoff marks).
i.e. (520/7)*120 = 89.14.
[520*120]/7 =86.14.
((Total Marks)/(No. of Students))*(outoff marks).
i.e. (520/7)*120 = 89.14.
[520*120]/7 =86.14.
Mouni said:
9 years ago
Simple= 520/100*120=624.
You can try to first divisible get 0 or canceled and got multiply 12*52=624.
You can try to first divisible get 0 or canceled and got multiply 12*52=624.
Rohit said:
9 years ago
80% of 120 is 96 not 90.
Mark gor said:
9 years ago
We can 1/7 * (90+80+70+80+85+65+50).
= 1/7 * 520.
= 74.2857 * 1.2 (full mark 120%) = 89.14.
= 1/7 * 520.
= 74.2857 * 1.2 (full mark 120%) = 89.14.
Samsam said:
9 years ago
@Akshata.
It's written 'percentage of marks' not just marks and yes 90% of 120 is not 90 but they have taken " % of 120" as common and grouped the percentage marks together for addition in the second step.
It's written 'percentage of marks' not just marks and yes 90% of 120 is not 90 but they have taken " % of 120" as common and grouped the percentage marks together for addition in the second step.
Anurag said:
1 decade ago
Two ways:
Either calculate the individual marks according to the percentage of marks given in the table. Then add all the marks and divide it by 7 to find out the Average marks.
Or
Do the sumtotal of all the percentage and then calculate the total marks for all the student and then divide by 7 to get the average marks.
Thanks.
Either calculate the individual marks according to the percentage of marks given in the table. Then add all the marks and divide it by 7 to find out the Average marks.
Or
Do the sumtotal of all the percentage and then calculate the total marks for all the student and then divide by 7 to get the average marks.
Thanks.
Asd said:
2 decades ago
Because in the table % of marks obtained in each subjects are mentioned.
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