Data Interpretation - Table Charts - Discussion
Discussion Forum : Table Charts - Table Chart 3 (Q.No. 5)
Directions to Solve
The following table gives the percentage of marks obtained by seven students in six different subjects in an examination.
The Numbers in the Brackets give the Maximum Marks in Each Subject.
| Student | Subject (Max. Marks) | |||||
| Maths | Chemistry | Physics | Geography | History | Computer Science | |
| (150) | (130) | (120) | (100) | (60) | (40) | |
| Ayush | 90 | 50 | 90 | 60 | 70 | 80 |
| Aman | 100 | 80 | 80 | 40 | 80 | 70 |
| Sajal | 90 | 60 | 70 | 70 | 90 | 70 |
| Rohit | 80 | 65 | 80 | 80 | 60 | 60 |
| Muskan | 80 | 65 | 85 | 95 | 50 | 90 |
| Tanvi | 70 | 75 | 65 | 85 | 40 | 60 |
| Tarun | 65 | 35 | 50 | 77 | 80 | 80 |
5.
What is the overall percentage of Tarun?
Answer: Option
Explanation:
Aggregate marks obtained by Tarun
= [ (65% of 150) + (35% of 130) + (50% of 120)
+ ((77% of 100) + (80% of 60) + (80% of 40) ]
= [ 97.5 + 45.5 + 60 + 77 + 48 + 32 ]
= 360.
The maximum marks (of all the six subjects)
= (150 + 130 + 120 + 100 + 60 + 40)
= 600.
 Overall percentage of Tarun = |
 |
360 | x 100 |  |
% = 60%. |
| 600 |
Discussion:
20 comments Page 1 of 2.
Tom said:
1 decade ago
Hey everyone, please help me out here with sg.
Why do we assume that the subjects are not equal, i.e. they need to be weighted according to the maximum amount of points achievable in each?
I believe that if I achieve 15% in maths and 90% in CS, my overall performance will be 15%+90%/2= 52,5% and not 30,78% (15%x150+90%x40)/190 - after all, this is only fair.
Sticking to my above example, if maths test was 150, and CS was 1000 points, my overall result would be a stunning 80,21%, which I think would be a bit unfair, considering that I have just failed maths miserably.
Let me know what you think.
Why do we assume that the subjects are not equal, i.e. they need to be weighted according to the maximum amount of points achievable in each?
I believe that if I achieve 15% in maths and 90% in CS, my overall performance will be 15%+90%/2= 52,5% and not 30,78% (15%x150+90%x40)/190 - after all, this is only fair.
Sticking to my above example, if maths test was 150, and CS was 1000 points, my overall result would be a stunning 80,21%, which I think would be a bit unfair, considering that I have just failed maths miserably.
Let me know what you think.
Bhavhar said:
1 decade ago
Guys any shortcut for this sum?
Navi said:
1 decade ago
How to make calculation easy for this sum?
Banu said:
1 decade ago
Please say some shortcut.
Chaitanya said:
10 years ago
Percentage calculation simplification:
1% = 00 (two zeros) i.e. if we see one % symbol we can cancel two zeros.
If we find 2% symbols we can cancel zeros.
For ex: 90%150 = 9*15 = 135.
= 99%88 = 87.12.
1% = 00 (two zeros) i.e. if we see one % symbol we can cancel two zeros.
If we find 2% symbols we can cancel zeros.
For ex: 90%150 = 9*15 = 135.
= 99%88 = 87.12.
DaVid Kawlni said:
10 years ago
Why not aggregate marks divided by total number of subjects:
i.e. 360/6 = 60.
i.e. 360/6 = 60.
Jazz said:
10 years ago
@David.
Because 360 are not the marks 360 are the % that's why.
Because 360 are not the marks 360 are the % that's why.
K.niharika said:
10 years ago
It will become 65%.
Rita said:
9 years ago
No, 360 are marks not % and we can do following calculations.
i.e 360/6 = 60 it is right.
i.e 360/6 = 60 it is right.
Varun said:
9 years ago
@Rita.
This 60 you got is average marks of all 6 subs if all subjects are of equal weight. Which is not asked in the question?
We need a percentage of marks (all sub having different weights) so we take aggregate.
Marks and divide by total marks achievable.
This 60 you got is average marks of all 6 subs if all subjects are of equal weight. Which is not asked in the question?
We need a percentage of marks (all sub having different weights) so we take aggregate.
Marks and divide by total marks achievable.
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