Data Interpretation - Table Charts - Discussion
Discussion Forum : Table Charts - Table Chart 2 (Q.No. 4)
Directions to Solve
Study the following table and answer the questions.
Number of Candidates Appeared and Qualified in a Competitive Examination from Different States Over the Years.
| State | Year | |||||||||
| 1997 | 1998 | 1999 | 2000 | 2001 | ||||||
| App. | Qual. | App. | Qual. | App. | Qual. | App. | Qual. | App. | Qual. | |
| M | 5200 | 720 | 8500 | 980 | 7400 | 850 | 6800 | 775 | 9500 | 1125 |
| N | 7500 | 840 | 9200 | 1050 | 8450 | 920 | 9200 | 980 | 8800 | 1020 |
| P | 6400 | 780 | 8800 | 1020 | 7800 | 890 | 8750 | 1010 | 9750 | 1250 |
| Q | 8100 | 950 | 9500 | 1240 | 8700 | 980 | 9700 | 1200 | 8950 | 995 |
| R | 7800 | 870 | 7600 | 940 | 9800 | 1350 | 7600 | 945 | 7990 | 885 |
4.
What is the percentage of candidates qualified from State N for all the years together, over the candidates appeared from State N during all the years together?
Answer: Option
Explanation:
| Required percentage |
|
|||||||
|
||||||||
| = 11.15% |
![]](/_files/images/data-interpretation/common/15-sym-cbracket-h1.gif)
Discussion:
10 comments Page 1 of 1.
Umakant said:
1 decade ago
@Swathi.
Your calculation is wrong, it goes beyond 13% so, how we can get answer between 11.15 and 11.47%.
Please correct me if I m wrong. Thanks.
Your calculation is wrong, it goes beyond 13% so, how we can get answer between 11.15 and 11.47%.
Please correct me if I m wrong. Thanks.
(2)
Rakesh said:
1 decade ago
I think we can do the below:
4810/4315 = .48/.432(apprx) = .12/.108 = .03/.27 = .01/.09 = 1/9 = 100/9% = 11.111...%
4810/4315 = .48/.432(apprx) = .12/.108 = .03/.27 = .01/.09 = 1/9 = 100/9% = 11.111...%
(1)
Swathi said:
1 decade ago
4810---->4500.
43150---->40000.
4500/40000*100 = 11.25%.
So nearest value off our answer in options was 11.15%.
So the answer is D.
43150---->40000.
4500/40000*100 = 11.25%.
So nearest value off our answer in options was 11.15%.
So the answer is D.
(1)
Bhupathi mp said:
9 years ago
Hi, I can't understand this problem. Could anyone help me?
(1)
Reet said:
1 decade ago
I can do the first step but cannot understand how you calculate the second step.. Please help..
Srikanth reddy said:
1 decade ago
Any short cut please.
Ashima said:
1 decade ago
Within a short span of time how to do these calculations?
Bhoopathi.Ch said:
1 decade ago
Assume 10% of 43150 i.e., 4315.
4810 - 4315 = 495.
1% of 43150 is 431.50.
495-431.50 = 63.50.
63.50 is 0.15% of 43150.
Then add all 10%+1%+0.15% = 11.15%.
Try to consider the denominator parts as 1% , 10% to solve these kind of problems.
4810 - 4315 = 495.
1% of 43150 is 431.50.
495-431.50 = 63.50.
63.50 is 0.15% of 43150.
Then add all 10%+1%+0.15% = 11.15%.
Try to consider the denominator parts as 1% , 10% to solve these kind of problems.
Kapil Suryawanshi said:
1 decade ago
4810/43150*100 = 11.147 this is correct answer.
Why should you given the answer - 11.15?
Please reply me.
Why should you given the answer - 11.15?
Please reply me.
ChowdaReddy said:
1 decade ago
@Kapil, As you said exact value is 11.147 only but we have nearest value 11.15 in the options. You have to consider the most nearest value when there is no exact value.
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