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Discussion Forum : Table Charts  Table Chart 2 (Q.No. 4)
Directions to Solve
Study the following table and answer the questions.
Number of Candidates Appeared and Qualified in a Competitive Examination from Different States Over the Years.
State  Year  
1997  1998  1999  2000  2001  
App.  Qual.  App.  Qual.  App.  Qual.  App.  Qual.  App.  Qual.  
M  5200  720  8500  980  7400  850  6800  775  9500  1125 
N  7500  840  9200  1050  8450  920  9200  980  8800  1020 
P  6400  780  8800  1020  7800  890  8750  1010  9750  1250 
Q  8100  950  9500  1240  8700  980  9700  1200  8950  995 
R  7800  870  7600  940  9800  1350  7600  945  7990  885 
4.
What is the percentage of candidates qualified from State N for all the years together, over the candidates appeared from State N during all the years together?
Answer: Option
Explanation:
Required percentage 




= 11.15% 
Discussion:
10 comments Page 1 of 1.
Bhupathi mp said:
8 years ago
Hi, I can't understand this problem. Could anyone help me?
(1)
Umakant said:
10 years ago
@Swathi.
Your calculation is wrong, it goes beyond 13% so, how we can get answer between 11.15 and 11.47%.
Please correct me if I m wrong. Thanks.
Your calculation is wrong, it goes beyond 13% so, how we can get answer between 11.15 and 11.47%.
Please correct me if I m wrong. Thanks.
(2)
Swathi said:
10 years ago
4810>4500.
43150>40000.
4500/40000*100 = 11.25%.
So nearest value off our answer in options was 11.15%.
So the answer is D.
43150>40000.
4500/40000*100 = 11.25%.
So nearest value off our answer in options was 11.15%.
So the answer is D.
(1)
ChowdaReddy said:
1 decade ago
@Kapil, As you said exact value is 11.147 only but we have nearest value 11.15 in the options. You have to consider the most nearest value when there is no exact value.
Kapil Suryawanshi said:
1 decade ago
4810/43150*100 = 11.147 this is correct answer.
Why should you given the answer  11.15?
Please reply me.
Why should you given the answer  11.15?
Please reply me.
Rakesh said:
1 decade ago
I think we can do the below:
4810/4315 = .48/.432(apprx) = .12/.108 = .03/.27 = .01/.09 = 1/9 = 100/9% = 11.111...%
4810/4315 = .48/.432(apprx) = .12/.108 = .03/.27 = .01/.09 = 1/9 = 100/9% = 11.111...%
(1)
Bhoopathi.Ch said:
1 decade ago
Assume 10% of 43150 i.e., 4315.
4810  4315 = 495.
1% of 43150 is 431.50.
495431.50 = 63.50.
63.50 is 0.15% of 43150.
Then add all 10%+1%+0.15% = 11.15%.
Try to consider the denominator parts as 1% , 10% to solve these kind of problems.
4810  4315 = 495.
1% of 43150 is 431.50.
495431.50 = 63.50.
63.50 is 0.15% of 43150.
Then add all 10%+1%+0.15% = 11.15%.
Try to consider the denominator parts as 1% , 10% to solve these kind of problems.
Ashima said:
1 decade ago
Within a short span of time how to do these calculations?
Srikanth reddy said:
1 decade ago
Any short cut please.
Reet said:
1 decade ago
I can do the first step but cannot understand how you calculate the second step.. Please help..
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