# Data Interpretation - Table Charts - Discussion

### Discussion :: Table Charts - Table Chart 2 (Q.No.5)

Study the following table and answer the questions.

Number of Candidates Appeared and Qualified in a Competitive Examination from Different States Over the Years.

 State Year 1997 1998 1999 2000 2001 App. Qual. App. Qual. App. Qual. App. Qual. App. Qual. M 5200 720 8500 980 7400 850 6800 775 9500 1125 N 7500 840 9200 1050 8450 920 9200 980 8800 1020 P 6400 780 8800 1020 7800 890 8750 1010 9750 1250 Q 8100 950 9500 1240 8700 980 9700 1200 8950 995 R 7800 870 7600 940 9800 1350 7600 945 7990 885

5.

The percentage of total number of qualified candidates to the total number of appeared candidates among all the five states in 1999 is?

 [A]. 11.49% [B]. 11.84% [C]. 12.21% [D]. 12.57%

Explanation:

Required percentage
 = (850 + 920 + 890 + 980 + 1350) x 100 % (7400 + 8450 + 7800 + 8700 + 9800)
 = 4990 x 100 % 42150
= 11.84%.

 Hemanth said: (Oct 16, 2014) How to add & divide in easy way?

 Rajnish said: (Apr 4, 2015) 1st way: (4990) or 5000 approximately -2000 ~ 4800. = 42150-2000~40000. So 4800/40000*100 = 12 actual just less near 12 so answer = 11.84. 2nd way: 4.990/4.215*10 ~ 5/4.2*10 = 1/20/1/24 (using fraction) = 1.2*10 = 12%. So answer just less = 11.84.

 Ashwini said: (Jul 18, 2017) How you have taken 4800 only as approximate? Because nearest for 4990 is 5000. Can you please explain?

 Guna said: (Apr 28, 2018) I can't understand. Please explain me.

 Ananthraj Vijayakumar said: (Aug 23, 2018) Please follow the below method. i.e., 4990 = 5000 & 42150 = 42000. Now, 5000/42000*100 = 11.90. The nearest value is 11.84. Hence, take that as an answer.

 Sneha said: (Feb 18, 2019) I can't understand it. Please anyone explain the calculations.

 Mandy said: (Nov 10, 2019) The value 840 is showed in the calculation but there is no such value in table similarly for value 7500.

 Rohith said: (May 26, 2020) Please explain me.

 Dileep said: (Jul 9, 2021) Please explain me to get it.