Data Interpretation - Table Charts - Discussion

Discussion Forum : Table Charts - Table Chart 1 (Q.No. 1)
Directions to Solve

Study the following table and answer the questions based on it.

Expenditures of a Company (in Lakh Rupees) per Annum Over the given Years.

Year Item of Expenditure
Salary Fuel and Transport Bonus Interest on Loans Taxes
1998288983.0023.483
19993421122.5232.5108
20003241013.8441.674
20013361333.6836.488
20024201423.9649.498


1.
What is the average amount of interest per year which the company had to pay during this period?
Rs. 32.43 lakhs
Rs. 33.72 lakhs
Rs. 34.18 lakhs
Rs. 36.66 lakhs
Answer: Option
Explanation:

Average amount of interest paid by the Company during the given period

    = Rs. [ 23.4 + 32.5 + 41.6 + 36.4 + 49.4 ] lakhs
5

    = Rs. [ 183.3 ] lakhs
5

    = Rs. 36.66 lakhs.

Discussion:
49 comments Page 2 of 5.

Hilal said:   8 years ago
According to me, the answer is 35.66.
(6)

Deeksha K said:   10 months ago
I too agree, Rs.36.66 lakhs is the correct answer.
(5)

Manju sri said:   8 years ago
183.3÷5=36.63,when we divide the numerator by 5, double the numerator and move the decimal to left side.
(4)

Pallavi said:   9 months ago
Agree, 36.66 is the right answer.
(4)

Rajneet kaur said:   12 months ago
@All.

Please tell me the formula which is applied here.
(3)

Rahat Abdul Subhan Qureshi said:   2 years ago
I agree with the given answer. Thanks all for explaining the answer.
(3)

Shalini S Kovalan said:   8 years ago
Here, we need to add the Interest and Divide by the no.of years 183.33*5 = 36.63.
(3)

Sree said:   10 years ago
As Sandip said 183.3 * 20. If we are calculating all the interest on loans we are not getting that value.
(3)

Balaswamy said:   1 decade ago
To find the answer for this question is very easy, How?

Just add all the decimals and divide by 5 (23/5 = 4.6).

So find the answer which has last digit 6, it is none other than answer D (36.66).
(3)

Rajeev said:   1 decade ago
Add the smallest and largest value and divide with 2. you will get nearest value.

Here it is,
(23.4+49.4)/2 gives 36.4 (nearest value).
(2)


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