# Civil Engineering - Water Supply Engineering - Discussion

Discussion Forum : Water Supply Engineering - Section 1 (Q.No. 13)

13.

Distribution mains of any water supply, is normally designed for its average daily requirement

Discussion:

23 comments Page 1 of 3.
Sheikh Ovais Ahmed said:
2 years ago

225% is correct.

Water mains are Designed for a maximum of ( Max hourly demand or Coincident draft).

Maximum hourly demand = 270% of av hourly demand (i.e. 2.7 * Qav).

Coincident Draft includes Maximum daily demand which is 180% of Average daily demand (i.e. 1.8 * Qav).

Thus we take an average of these two (270+180)/2 = 225%.

I hope this is clarified.

Water mains are Designed for a maximum of ( Max hourly demand or Coincident draft).

Maximum hourly demand = 270% of av hourly demand (i.e. 2.7 * Qav).

Coincident Draft includes Maximum daily demand which is 180% of Average daily demand (i.e. 1.8 * Qav).

Thus we take an average of these two (270+180)/2 = 225%.

I hope this is clarified.

(13)

Moyir said:
2 years ago

For daily it's 180%, for hourly it's 150%, for monthly it's 140%.

(1)

Sheikh Ovais Ahmed said:
2 years ago

225% is correct.

Water mains are Designed for a maximum of ( Max hourly demand or Coincident draft).

Maximum hourly demand = 270% of av hourly demand (i.e. 2.7 * Qav).

Coincident Draft includes Maximum daily demand which is 180% of Average daily demand (i.e. 1.8 * Qav).

Thus we take an average of these two (270+180)/2 = 225%.

I hope this is clarified.

Water mains are Designed for a maximum of ( Max hourly demand or Coincident draft).

Maximum hourly demand = 270% of av hourly demand (i.e. 2.7 * Qav).

Coincident Draft includes Maximum daily demand which is 180% of Average daily demand (i.e. 1.8 * Qav).

Thus we take an average of these two (270+180)/2 = 225%.

I hope this is clarified.

(1)

Vinay Kumar said:
5 years ago

Maximum daily demand = 1.8 x average daily demand.

Maximum hourly demand of maximum day i.e. Peak demand.

= 1.5 x average hourly demand.

= 1.5 x Maximum daily demand/24.

= 1.5 x (1.8 x average daily demand)/24.

= 2.7 x average daily demand/24.

= 2.7 x annual average hourly demand.

Maximum hourly demand of maximum day i.e. Peak demand.

= 1.5 x average hourly demand.

= 1.5 x Maximum daily demand/24.

= 1.5 x (1.8 x average daily demand)/24.

= 2.7 x average daily demand/24.

= 2.7 x annual average hourly demand.

(1)

Hamid raza hashmi said:
6 years ago

180% is correct. I agree with it.

Abhishek Das said:
3 years ago

If daily then 180% and if hourly then 150%.

Ashwani Kumar said:
4 years ago

The question is wrong.

Generally distribution system should be designed for maximum hourly consumption of maximum day i.e. Peak Demand or Coincident draft, whichever is more.

God-rich formula to find peak demand to an average demand ratio.

P = 180 x t^ (-0. 1)

Where P = percent of the annual average draft for the time 't' in days.

So, I think 180% is the right answer.

Generally distribution system should be designed for maximum hourly consumption of maximum day i.e. Peak Demand or Coincident draft, whichever is more.

God-rich formula to find peak demand to an average demand ratio.

P = 180 x t^ (-0. 1)

Where P = percent of the annual average draft for the time 't' in days.

So, I think 180% is the right answer.

Chaman said:
4 years ago

Thanks everyone for explaining it.

Monika said:
4 years ago

I don't understand? Please explain me clearly.

Aravind said:
5 years ago

Design criteria - coincidental draft or max hourly demand.

Max hourly demand = 1.5 x max daily demand.

= 2.7 x avg daily demand.

= 270%.

Max hourly demand = 1.5 x max daily demand.

= 2.7 x avg daily demand.

= 270%.

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