Civil Engineering - Water Resources Engineering - Discussion

Discussion Forum : Water Resources Engineering - Section 1 (Q.No. 36)
36.
If the potential infiltration of a water shed having a soil with fair pasture cover, is 10 cm and rainfall is 12 cm, the direct run off is :
2 cm
3 cm
5 cm
8 cm.
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
14 comments Page 1 of 2.

Nitesh said:   1 decade ago
Can I get the explanation for this question please?

Murali krishna said:   1 decade ago
Capacity 10 cm rainfall 12 cm then runoff will be 12-10 = 2.

Then how the answer became 5.

TANMOY SAHA said:   1 decade ago
Guys, please refer question no-35.

Pankaj bhatt said:   1 decade ago
for Direct Run off.
Q = (P-0.2S)^2/(P-0.8S).

Put Value In Equation.

P = 12 and S = 10,
We Will Get Q = 5cm.

Kumar said:   1 decade ago
For direct runoff.

Q = (P-0.2S)^2/(P+0.8S).

Put p=12 and s=10 in above equation,

We will get Q=5 cm.
(1)

Arun singh said:   1 decade ago
Formula is not correct. Correct formula is Q = (p-0.2s)^2/(p-0.8s).
(1)

Tushar said:   10 years ago
Instead of square of above you select option C, then how is its same. In 35 answer is it article's or five?

Arindam Mahanty said:   9 years ago
The correct formula is;

Q = (P-0.2S)^S/(P+0.8S).
(2)

Muniraj jodli said:   8 years ago
The direct runoff.

Q = (P-0.2S)^2/(P+0.8S).Put p=12 and s=10.

We will get Q=5 cm.
(3)

Bidyut Barman said:   8 years ago
Direct runoff= Surface runoff-prompt Interflow.
=12-10=2 cm.


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