Civil Engineering - Water Resources Engineering - Discussion
Discussion Forum : Water Resources Engineering - Section 1 (Q.No. 36)
36.
If the potential infiltration of a water shed having a soil with fair pasture cover, is 10 cm and rainfall is 12 cm, the direct run off is :
Discussion:
14 comments Page 1 of 2.
GIRISH said:
4 years ago
Please explain me the answer with the formula.
(1)
Imtiaz hakim said:
5 years ago
The actual formula is Q = (P-0.2S)^S/(P+0.8S).
Q = (12-2)^10 /(12+8),
= 100/20,
= 5.
Q = (12-2)^10 /(12+8),
= 100/20,
= 5.
(4)
DUTESH KUMAR said:
7 years ago
By using direct run off formula.
(P-0.2s)^2/p+.8s.
(P-0.2s)^2/p+.8s.
(2)
Bidyut Barman said:
8 years ago
Direct runoff =Total runoff-Base flow=12-10 =10 cm.
Bidyut Barman said:
8 years ago
Direct runoff= Surface runoff-prompt Interflow.
=12-10=2 cm.
=12-10=2 cm.
Muniraj jodli said:
8 years ago
The direct runoff.
Q = (P-0.2S)^2/(P+0.8S).Put p=12 and s=10.
We will get Q=5 cm.
Q = (P-0.2S)^2/(P+0.8S).Put p=12 and s=10.
We will get Q=5 cm.
(3)
Arindam Mahanty said:
9 years ago
The correct formula is;
Q = (P-0.2S)^S/(P+0.8S).
Q = (P-0.2S)^S/(P+0.8S).
(2)
Tushar said:
10 years ago
Instead of square of above you select option C, then how is its same. In 35 answer is it article's or five?
Arun singh said:
1 decade ago
Formula is not correct. Correct formula is Q = (p-0.2s)^2/(p-0.8s).
(1)
Kumar said:
1 decade ago
For direct runoff.
Q = (P-0.2S)^2/(P+0.8S).
Put p=12 and s=10 in above equation,
We will get Q=5 cm.
Q = (P-0.2S)^2/(P+0.8S).
Put p=12 and s=10 in above equation,
We will get Q=5 cm.
(1)
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