Civil Engineering - Waste Water Engineering - Discussion
Discussion Forum : Waste Water Engineering - Section 3 (Q.No. 23)
23.
For trunk sewers more than 1.25 m in diameter, the ratio of the maximum daily sewage flow to the average daily sewage flow is assumed
Discussion:
13 comments Page 1 of 2.
Ankit agrawal said:
6 years ago
Max. daily sewage flow = 1.8,
Max. hourly sewage flow = 1.5,
Given trunk dia. = 1.25,
Ratio = 1.25*1.8/ 1.5 = 1.5 (answer).
Max. hourly sewage flow = 1.5,
Given trunk dia. = 1.25,
Ratio = 1.25*1.8/ 1.5 = 1.5 (answer).
(4)
Dipu bunku rose said:
6 years ago
The given answer is correct.
(1)
Ankit said:
9 years ago
Please give me the explanation for this.
Gayatri said:
8 years ago
Please explain anyone.
Praveen said:
8 years ago
Option: B) 2 is correct.
Dinesh said:
8 years ago
Option 2 is correct one.
Arnab said:
8 years ago
Option A is correct.
Priya said:
7 years ago
How option A is correct ? Please explain.
Priyanka Shah said:
7 years ago
Please, someone explain it in clear.
Rajashree pany said:
6 years ago
Maximum daily sewage = 2 * average daily sewage.
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