Civil Engineering - Waste Water Engineering - Discussion

23. 

For trunk sewers more than 1.25 m in diameter, the ratio of the maximum daily sewage flow to the average daily sewage flow is assumed

[A]. 1.5
[B]. 2.0
[C]. 2.5
[D]. 3.0
[E]. 3.5

Answer: Option A

Explanation:

No answer description available for this question.

Ankit said: (Feb 8, 2017)  
Please give me the explanation for this.

Gayatri said: (Jun 21, 2017)  
Please explain anyone.

Praveen said: (Sep 8, 2017)  
Option: B) 2 is correct.

Dinesh said: (Sep 13, 2017)  
Option 2 is correct one.

Arnab said: (Jan 15, 2018)  
Option A is correct.

Priya said: (Apr 25, 2018)  
How option A is correct ? Please explain.

Priyanka Shah said: (Mar 12, 2019)  
Please, someone explain it in clear.

Rajashree Pany said: (Jul 15, 2019)  
Maximum daily sewage = 2 * average daily sewage.

Dheeraj said: (Feb 8, 2020)  
Option B is correct. Because this question is also has been asked in previous sections.

Kaku said: (Feb 20, 2020)  
Option A is correct because average daily sewage flow is always considered 1.5.

Hisham said: (Feb 20, 2020)  
1.5 for hourly variation (Garg page. 12).
Here its daily. So 2 is the correct ratio.

Dipu Bunku Rose said: (Feb 24, 2020)  
The given answer is correct.

Ankit Agrawal said: (Apr 5, 2020)  
Max. daily sewage flow = 1.8,
Max. hourly sewage flow = 1.5,
Given trunk dia. = 1.25,
Ratio = 1.25*1.8/ 1.5 = 1.5 (answer).

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