# Civil Engineering - Waste Water Engineering - Discussion

### Discussion :: Waste Water Engineering - Section 3 (Q.No.23)

23.

For trunk sewers more than 1.25 m in diameter, the ratio of the maximum daily sewage flow to the average daily sewage flow is assumed

 [A]. 1.5 [B]. 2 [C]. 2.5 [D]. 3 [E]. 3.5

Explanation:

No answer description available for this question.

 Ankit said: (Feb 8, 2017) Please give me the explanation for this.

 Gayatri said: (Jun 21, 2017) Please explain anyone.

 Praveen said: (Sep 8, 2017) Option: B) 2 is correct.

 Dinesh said: (Sep 13, 2017) Option 2 is correct one.

 Arnab said: (Jan 15, 2018) Option A is correct.

 Priya said: (Apr 25, 2018) How option A is correct ? Please explain.

 Priyanka Shah said: (Mar 12, 2019) Please, someone explain it in clear.

 Rajashree Pany said: (Jul 15, 2019) Maximum daily sewage = 2 * average daily sewage.

 Dheeraj said: (Feb 8, 2020) Option B is correct. Because this question is also has been asked in previous sections.

 Kaku said: (Feb 20, 2020) Option A is correct because average daily sewage flow is always considered 1.5.

 Hisham said: (Feb 20, 2020) 1.5 for hourly variation (Garg page. 12). Here its daily. So 2 is the correct ratio.

 Dipu Bunku Rose said: (Feb 24, 2020) The given answer is correct.

 Ankit Agrawal said: (Apr 5, 2020) Max. daily sewage flow = 1.8, Max. hourly sewage flow = 1.5, Given trunk dia. = 1.25, Ratio = 1.25*1.8/ 1.5 = 1.5 (answer).