Civil Engineering - Waste Water Engineering - Discussion
Discussion Forum : Waste Water Engineering - Section 4 (Q.No. 10)
10.
The sewage discharge in a detritus tank of a treatment plant is 576 litres/sec with flow velocity of 0.2 m/sec. If the ratio of width to depth is 2, the depth is
Discussion:
12 comments Page 1 of 2.
Er zeeshan said:
2 years ago
b/d=2,b=2d
Q = AV ,
A = Q/V = 576 * 10^-3/0.2 = 2.88m2.
A = B * D,
2.88 = 2D*D,
D = 1.2m = 1.2 * 10 = 120cm => answer.
Q = AV ,
A = Q/V = 576 * 10^-3/0.2 = 2.88m2.
A = B * D,
2.88 = 2D*D,
D = 1.2m = 1.2 * 10 = 120cm => answer.
(2)
Ghani said:
4 years ago
Good explanation. Thanks.
Jabran Khan said:
5 years ago
Thanks for explaining @Rajeev Yadav.
(1)
Mary gevency said:
6 years ago
Thank you all.
Deepak yadav said:
7 years ago
Thank you @Rajeev Yadav.
Abhijeet said:
7 years ago
Thank you @Rajeev.
Raj said:
7 years ago
Thank you @Rajeev.
Msr said:
8 years ago
Thank you @Rajeev.
Megha said:
8 years ago
Thanks @Rajeev Yadav.
Gayatri said:
8 years ago
Yeah, you are right, I agree with you @Rajeev Yadav.
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