Civil Engineering - Waste Water Engineering - Discussion
Discussion Forum : Waste Water Engineering - Section 4 (Q.No. 10)
10.
The sewage discharge in a detritus tank of a treatment plant is 576 litres/sec with flow velocity of 0.2 m/sec. If the ratio of width to depth is 2, the depth is
Discussion:
12 comments Page 2 of 2.
Mukesh maurya said:
9 years ago
I agree with you @Rajeev Yadav.
Rajeev yadav said:
1 decade ago
Given.
Q = 576 lit/sec, means Q = 0.576 m^3/sec because (1 m^3 = 1000 lit).
Also given v = 0.2 m/sec.
We know that Q = A*V,
So A = Q/V = 0.576/0.2 = 2.88 m^2,
Also given width/depth = 2 means b = 2*d.
So A = b*d = 2.88, given b = 2d.
So 2d*d = 2.88. So d^2 = 1.44.
So d =under root 1.44, d = 1.2 m = 1.2*100 = 120 cm.
Q = 576 lit/sec, means Q = 0.576 m^3/sec because (1 m^3 = 1000 lit).
Also given v = 0.2 m/sec.
We know that Q = A*V,
So A = Q/V = 0.576/0.2 = 2.88 m^2,
Also given width/depth = 2 means b = 2*d.
So A = b*d = 2.88, given b = 2d.
So 2d*d = 2.88. So d^2 = 1.44.
So d =under root 1.44, d = 1.2 m = 1.2*100 = 120 cm.
(2)
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