Civil Engineering - Waste Water Engineering - Discussion
Discussion Forum : Waste Water Engineering - Section 4 (Q.No. 10)
10.
The sewage discharge in a detritus tank of a treatment plant is 576 litres/sec with flow velocity of 0.2 m/sec. If the ratio of width to depth is 2, the depth is
Discussion:
12 comments Page 1 of 2.
Rajeev yadav said:
1 decade ago
Given.
Q = 576 lit/sec, means Q = 0.576 m^3/sec because (1 m^3 = 1000 lit).
Also given v = 0.2 m/sec.
We know that Q = A*V,
So A = Q/V = 0.576/0.2 = 2.88 m^2,
Also given width/depth = 2 means b = 2*d.
So A = b*d = 2.88, given b = 2d.
So 2d*d = 2.88. So d^2 = 1.44.
So d =under root 1.44, d = 1.2 m = 1.2*100 = 120 cm.
Q = 576 lit/sec, means Q = 0.576 m^3/sec because (1 m^3 = 1000 lit).
Also given v = 0.2 m/sec.
We know that Q = A*V,
So A = Q/V = 0.576/0.2 = 2.88 m^2,
Also given width/depth = 2 means b = 2*d.
So A = b*d = 2.88, given b = 2d.
So 2d*d = 2.88. So d^2 = 1.44.
So d =under root 1.44, d = 1.2 m = 1.2*100 = 120 cm.
(2)
Er zeeshan said:
2 years ago
b/d=2,b=2d
Q = AV ,
A = Q/V = 576 * 10^-3/0.2 = 2.88m2.
A = B * D,
2.88 = 2D*D,
D = 1.2m = 1.2 * 10 = 120cm => answer.
Q = AV ,
A = Q/V = 576 * 10^-3/0.2 = 2.88m2.
A = B * D,
2.88 = 2D*D,
D = 1.2m = 1.2 * 10 = 120cm => answer.
(2)
Gayatri said:
8 years ago
Yeah, you are right, I agree with you @Rajeev Yadav.
Jabran Khan said:
5 years ago
Thanks for explaining @Rajeev Yadav.
(1)
Mukesh maurya said:
9 years ago
I agree with you @Rajeev Yadav.
Ghani said:
4 years ago
Good explanation. Thanks.
Deepak yadav said:
7 years ago
Thank you @Rajeev Yadav.
Megha said:
8 years ago
Thanks @Rajeev Yadav.
Msr said:
8 years ago
Thank you @Rajeev.
Raj said:
7 years ago
Thank you @Rajeev.
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