Civil Engineering - Waste Water Engineering - Discussion

Discussion Forum : Waste Water Engineering - Section 3 (Q.No. 36)
36.
For the open drain (N = 0.025) shown in the below figure, the discharge is
26.88 cumecs
27.88 cumecs
28.88 cumecs
29.88 cumecs.
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
17 comments Page 1 of 2.

D H Unnadpotra said:   7 years ago
Area = 7.2 m2.
Perimeter P=7.2 m.
Therefore Hydraulic radius R = 1 m, n = 0.025.
S = 1 and now when put these all values in manning's equation, V = 288 m/sec and Discharge Q = 39.82 cumecs.

How it comes 28.88 cumecs? Please tell me.

ILA SAQAW said:   3 years ago
Area = 7.2 sqr-m.

Perimeter= 7.252 m.
Hydr. R = 0.99 say 1.

Assume the slope of 1 in 100.

V = 1/0.025 x (1) ^ 2/3 x (1/100)^ 1/2.
V = 4 m/sec.
Q = A x V.
Q = 7.2 Sqr-m * 4 m/sec,
Q= 28.8 cumec.
(2)

Dheeraj said:   6 years ago
It is very simple guys:

The formula for Area of trapezoidal tank =Bd +sd^2.
B - width.
d - depth.
S - slope(1vertical is to 1 horizontal i.e, =1).

So, Area is (1.6 x 2)+(2^2)=7.2.
So 7.2/.025 = 288.
(1)

Haris khan said:   6 years ago
A= D (B+(B+2nD)/2).

Here D = 2
B = 1.6
n = 1( which is given as slope 1:1 we will take the base i.e horizontal)
So, Area = 7.2.

Pravin said:   8 years ago
The Area is not considered in calculation. R is mean hydraulic radius i.e. area divided by wetted perimeter.

Anomie said:   7 years ago
Area =7.2,
n=0.025,
R=d/2=2/2=1,
s=1.

Use manning eqn to find vel.
q = 28.88 cumecs.

SHEKHAR JANA said:   8 years ago
Ratio of lateral axis should 1is 2, then area = 7.2 m2, 7.2/.025 = 2.88.

Pronay said:   3 years ago
@ILA SAQAW.

How perimeter is 7.2? Please explain.

Gosa alemayehu said:   7 years ago
Please given the clear description for the answer.

Noorzaman said:   3 years ago
Anyone, Please explain me the velocity formula.


Post your comments here:

Your comments will be displayed after verification.