Civil Engineering - Waste Water Engineering - Discussion
Discussion Forum : Waste Water Engineering - Section 3 (Q.No. 36)
36.
For the open drain (N = 0.025) shown in the below figure, the discharge is
Discussion:
17 comments Page 1 of 2.
Gani said:
10 years ago
Where is slope?
Shruthi said:
10 years ago
Please explain.
Abdullah talip said:
9 years ago
Assume slope = 0.01 in Hazen equation.
TAYEB said:
9 years ago
AREA = 7.2 M2.
7.2/0.025 = 2.88.
7.2/0.025 = 2.88.
Harsha said:
8 years ago
Can anyone explain clearly?
SHEKHAR JANA said:
8 years ago
Ratio of lateral axis should 1is 2, then area = 7.2 m2, 7.2/.025 = 2.88.
Pravin said:
8 years ago
The Area is not considered in calculation. R is mean hydraulic radius i.e. area divided by wetted perimeter.
Gosa alemayehu said:
7 years ago
Please given the clear description for the answer.
Anomie said:
7 years ago
Area =7.2,
n=0.025,
R=d/2=2/2=1,
s=1.
Use manning eqn to find vel.
q = 28.88 cumecs.
n=0.025,
R=d/2=2/2=1,
s=1.
Use manning eqn to find vel.
q = 28.88 cumecs.
D H Unnadpotra said:
7 years ago
Area = 7.2 m2.
Perimeter P=7.2 m.
Therefore Hydraulic radius R = 1 m, n = 0.025.
S = 1 and now when put these all values in manning's equation, V = 288 m/sec and Discharge Q = 39.82 cumecs.
How it comes 28.88 cumecs? Please tell me.
Perimeter P=7.2 m.
Therefore Hydraulic radius R = 1 m, n = 0.025.
S = 1 and now when put these all values in manning's equation, V = 288 m/sec and Discharge Q = 39.82 cumecs.
How it comes 28.88 cumecs? Please tell me.
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