Discussion :: Waste Water Engineering - Section 3 (Q.No.36)
For the open drain (N = 0.025) shown in the below figure, the discharge is
Answer: Option C
No answer description available for this question.
|Gani said: (Dec 11, 2015)|
|Where is slope?|
|Shruthi said: (Feb 1, 2016)|
|Abdullah Talip said: (Jun 30, 2016)|
|Assume slope = 0.01 in Hazen equation.|
|Tayeb said: (Nov 22, 2016)|
|AREA = 7.2 M2.
7.2/0.025 = 2.88.
|Harsha said: (Jul 29, 2017)|
|Can anyone explain clearly?|
|Shekhar Jana said: (Nov 11, 2017)|
|Ratio of lateral axis should 1is 2, then area = 7.2 m2, 7.2/.025 = 2.88.|
|Pravin said: (Feb 7, 2018)|
|The Area is not considered in calculation. R is mean hydraulic radius i.e. area divided by wetted perimeter.|
|Gosa Alemayehu said: (Oct 25, 2018)|
|Please given the clear description for the answer.|
|Anomie said: (Jan 8, 2019)|
Use manning eqn to find vel.
q = 28.88 cumecs.
|D H Unnadpotra said: (Jan 9, 2019)|
|Area = 7.2 m2.
Perimeter P=7.2 m.
Therefore Hydraulic radius R = 1 m, n = 0.025.
S = 1 and now when put these all values in manning's equation, V = 288 m/sec and Discharge Q = 39.82 cumecs.
How it comes 28.88 cumecs? Please tell me.
|Kruthi said: (Jun 17, 2019)|
|How to calculate the area? Please tell me.|
|Haris Khan said: (Sep 5, 2019)|
|A= D (B+(B+2nD)/2).
Here D = 2
B = 1.6
n = 1( which is given as slope 1:1 we will take the base i.e horizontal)
So, Area = 7.2.
|Dheeraj said: (Feb 8, 2020)|
|It is very simple guys:
The formula for Area of trapezoidal tank =Bd +sd^2.
B - width.
d - depth.
S - slope(1vertical is to 1 horizontal i.e, =1).
So, Area is (1.6 x 2)+(2^2)=7.2.
So 7.2/.025 = 288.
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