Civil Engineering - Waste Water Engineering - Discussion

36. 

For the open drain (N = 0.025) shown in the below figure, the discharge is

[A]. 26.88 cumecs
[B]. 27.88 cumecs
[C]. 28.88 cumecs
[D]. 29.88 cumecs.

Answer: Option C

Explanation:

No answer description available for this question.

Gani said: (Dec 11, 2015)  
Where is slope?

Shruthi said: (Feb 1, 2016)  
Please explain.

Abdullah Talip said: (Jun 30, 2016)  
Assume slope = 0.01 in Hazen equation.

Tayeb said: (Nov 22, 2016)  
AREA = 7.2 M2.
7.2/0.025 = 2.88.

Harsha said: (Jul 29, 2017)  
Can anyone explain clearly?

Shekhar Jana said: (Nov 11, 2017)  
Ratio of lateral axis should 1is 2, then area = 7.2 m2, 7.2/.025 = 2.88.

Pravin said: (Feb 7, 2018)  
The Area is not considered in calculation. R is mean hydraulic radius i.e. area divided by wetted perimeter.

Gosa Alemayehu said: (Oct 25, 2018)  
Please given the clear description for the answer.

Anomie said: (Jan 8, 2019)  
Area =7.2,
n=0.025,
R=d/2=2/2=1,
s=1.

Use manning eqn to find vel.
q = 28.88 cumecs.

D H Unnadpotra said: (Jan 9, 2019)  
Area = 7.2 m2.
Perimeter P=7.2 m.
Therefore Hydraulic radius R = 1 m, n = 0.025.
S = 1 and now when put these all values in manning's equation, V = 288 m/sec and Discharge Q = 39.82 cumecs.

How it comes 28.88 cumecs? Please tell me.

Kruthi said: (Jun 17, 2019)  
How to calculate the area? Please tell me.

Haris Khan said: (Sep 5, 2019)  
A= D (B+(B+2nD)/2).

Here D = 2
B = 1.6
n = 1( which is given as slope 1:1 we will take the base i.e horizontal)
So, Area = 7.2.

Dheeraj said: (Feb 8, 2020)  
It is very simple guys:

The formula for Area of trapezoidal tank =Bd +sd^2.
B - width.
d - depth.
S - slope(1vertical is to 1 horizontal i.e, =1).

So, Area is (1.6 x 2)+(2^2)=7.2.
So 7.2/.025 = 288.

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