Civil Engineering - Theory of Structures - Discussion
Discussion Forum : Theory of Structures - Section 1 (Q.No. 7)
7.
In the truss shown in the given figure, the force in member BC is
Discussion:
25 comments Page 3 of 3.
Tyrion lanister said:
1 decade ago
At joint C there in neither any external force nor any support to give reaction. Hence BC and DC are zero force members as there is no other force to balance the member forces.
Ritik kumar said:
1 decade ago
As f(bc)sin0 = zero at vertical equilibrium forces = 0.
Therefore f(bc) = 0.
Therefore f(bc) = 0.
Atul dabral said:
1 decade ago
Apply equation pf equilibrium at joint c. Hence there is no force at BC.
VIPUL GARG said:
1 decade ago
Here if we consider the equilibrium of pt. C,
In x direction, -f(cb)- f(cd)Cos 8 = 0.
& in y direction, -f(cd)Sin 8 = 0.
This gives, f(cd) = 0.
Therefore, f(cb) = 0.
Hence, option(C) is correct.
In x direction, -f(cb)- f(cd)Cos 8 = 0.
& in y direction, -f(cd)Sin 8 = 0.
This gives, f(cd) = 0.
Therefore, f(cb) = 0.
Hence, option(C) is correct.
Shahzaman said:
1 decade ago
What will be the answer in mathematical form?
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