Civil Engineering - Theory of Structures - Discussion

Discussion Forum : Theory of Structures - Section 1 (Q.No. 7)
7.
In the truss shown in the given figure, the force in member BC is
100 t compressive
100 t tensile
zero
indeterminate
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
25 comments Page 1 of 3.

Abhishek said:   1 decade ago
How?

It should be indeterminate.

Because there is no dimensions are given.

Here will be some horizontal thrust which we will calculate by taking moment.

Shahzaman said:   1 decade ago
What will be the answer in mathematical form?

VIPUL GARG said:   1 decade ago
Here if we consider the equilibrium of pt. C,

In x direction, -f(cb)- f(cd)Cos 8 = 0.
& in y direction, -f(cd)Sin 8 = 0.

This gives, f(cd) = 0.
Therefore, f(cb) = 0.

Hence, option(C) is correct.

Atul dabral said:   1 decade ago
Apply equation pf equilibrium at joint c. Hence there is no force at BC.

Ritik kumar said:   1 decade ago
As f(bc)sin0 = zero at vertical equilibrium forces = 0.

Therefore f(bc) = 0.

Tyrion lanister said:   1 decade ago
At joint C there in neither any external force nor any support to give reaction. Hence BC and DC are zero force members as there is no other force to balance the member forces.

Anshu said:   9 years ago
What is meant by truss?

Sandhya said:   9 years ago
At joint C there is only 2 members meet which are non collinear and there is no external force or reaction act at that joint. So the both member carry 0 force.

Mir Idrees said:   9 years ago
When we consider equilibrium at B it means a force of 100tN is in the member BD in the opp. Direction since there is no force acting at any section of the member BC so no force is required to make the equilibrium at c so the force in the member BC is zero.

Ranjit said:   9 years ago
There is no force on the joint C, so force in the member BC is zero.


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