Civil Engineering - Theory of Structures - Discussion
Discussion Forum : Theory of Structures - Section 1 (Q.No. 7)
7.
In the truss shown in the given figure, the force in member BC is
Discussion:
25 comments Page 1 of 3.
Mir Idrees said:
9 years ago
When we consider equilibrium at B it means a force of 100tN is in the member BD in the opp. Direction since there is no force acting at any section of the member BC so no force is required to make the equilibrium at c so the force in the member BC is zero.
VIPUL GARG said:
1 decade ago
Here if we consider the equilibrium of pt. C,
In x direction, -f(cb)- f(cd)Cos 8 = 0.
& in y direction, -f(cd)Sin 8 = 0.
This gives, f(cd) = 0.
Therefore, f(cb) = 0.
Hence, option(C) is correct.
In x direction, -f(cb)- f(cd)Cos 8 = 0.
& in y direction, -f(cd)Sin 8 = 0.
This gives, f(cd) = 0.
Therefore, f(cb) = 0.
Hence, option(C) is correct.
Ashish Kumar said:
5 years ago
CB &CD are zero force members. When two non-collinear members are meeting at a joint and if there is no external load on that joint, then force in those members becomes Zero.
Tyrion lanister said:
1 decade ago
At joint C there in neither any external force nor any support to give reaction. Hence BC and DC are zero force members as there is no other force to balance the member forces.
Muhammad Asif Mahmood said:
4 years ago
When two non-collinear members meet at a truss joint and there is no external applied load or reaction acting on that joint then both members are zero force members.
(1)
Instructor Merihun. T said:
8 years ago
There is no horizontal force conmponent on the truss. So at joint C, summation of force on x axis is zero. Therefore both member BC and AB are equal and are zero.
Sandhya said:
9 years ago
At joint C there is only 2 members meet which are non collinear and there is no external force or reaction act at that joint. So the both member carry 0 force.
Abhishek said:
1 decade ago
How?
It should be indeterminate.
Because there is no dimensions are given.
Here will be some horizontal thrust which we will calculate by taking moment.
It should be indeterminate.
Because there is no dimensions are given.
Here will be some horizontal thrust which we will calculate by taking moment.
Sharad Mane said:
9 years ago
Force transferred vertically direct. Hence at joint B, there is no horizontal forces at all. Hence Zero forces in BA, BC, and CD.
Tarun said:
9 years ago
@All. Once go through the zero member forces theory you will get the answer. So, the answer is zero.
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