Civil Engineering - Theory of Structures - Discussion
Discussion Forum : Theory of Structures - Section 1 (Q.No. 7)
7.
In the truss shown in the given figure, the force in member BC is
Discussion:
25 comments Page 3 of 3.
Ritik kumar said:
1 decade ago
As f(bc)sin0 = zero at vertical equilibrium forces = 0.
Therefore f(bc) = 0.
Therefore f(bc) = 0.
Atul dabral said:
1 decade ago
Apply equation pf equilibrium at joint c. Hence there is no force at BC.
VIPUL GARG said:
1 decade ago
Here if we consider the equilibrium of pt. C,
In x direction, -f(cb)- f(cd)Cos 8 = 0.
& in y direction, -f(cd)Sin 8 = 0.
This gives, f(cd) = 0.
Therefore, f(cb) = 0.
Hence, option(C) is correct.
In x direction, -f(cb)- f(cd)Cos 8 = 0.
& in y direction, -f(cd)Sin 8 = 0.
This gives, f(cd) = 0.
Therefore, f(cb) = 0.
Hence, option(C) is correct.
Shahzaman said:
1 decade ago
What will be the answer in mathematical form?
Abhishek said:
1 decade ago
How?
It should be indeterminate.
Because there is no dimensions are given.
Here will be some horizontal thrust which we will calculate by taking moment.
It should be indeterminate.
Because there is no dimensions are given.
Here will be some horizontal thrust which we will calculate by taking moment.
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