Civil Engineering - Surveying - Discussion
Discussion Forum : Surveying - Section 6 (Q.No. 30)
30.
The magnetic bearing of a line is 32° and the magnetic declination is 10° 15' W. The true bearing is
Discussion:
22 comments Page 1 of 3.
Fakhar Naveed said:
2 years ago
TRUE BEARING = MAGNETIC BEARING - MAGNECTIC DEC.
TB = 32' - 10'15' = 21'45'.
TB = 32' - 10'15' = 21'45'.
Rohan said:
5 years ago
I know A is the correct answer but will someone explain the solution without any misinformation!?
Mayur said:
5 years ago
A is the final and correct answer.
Nbn said:
6 years ago
magnetic meridian is measured from magnetic meridian i.e 10d15m west of true meridian (north). Hence it should be deducted. and the answer is correct
TSKD said:
7 years ago
MD = MB - TB.
10'15" = 32' - TB
-21'45" = -TB
Hence, TB = ANS "A".
10'15" = 32' - TB
-21'45" = -TB
Hence, TB = ANS "A".
(2)
Erk said:
7 years ago
The correct Answer should be B.
Shubham Umak said:
7 years ago
TB=MB+MD (if deflection toward east).
TB=MB-MD (if deflection toward west).
In this problem;
Given: MB=32degree.
And
MD = 10degree and 15 minutes (west).
Therefore;
TB=MB-MD{because deflection in west side is given that's why we take it negative).
TB=32'-10'15' = 21'45'.
Hence answer A is correct.
TB=MB-MD (if deflection toward west).
In this problem;
Given: MB=32degree.
And
MD = 10degree and 15 minutes (west).
Therefore;
TB=MB-MD{because deflection in west side is given that's why we take it negative).
TB=32'-10'15' = 21'45'.
Hence answer A is correct.
(2)
Thakur said:
7 years ago
Right ans is B.
First, we have to this in whole circle bearing,
So, 180-32=148,
Tb=148-10.45=137.55,
180-137.55=42.15.
First, we have to this in whole circle bearing,
So, 180-32=148,
Tb=148-10.45=137.55,
180-137.55=42.15.
Nagender thakur said:
7 years ago
B is the right answer.
Kamlesh said:
8 years ago
Option A is correct.
If quadrantel bearing is given then option B will be correct @Pooja.
If quadrantel bearing is given then option B will be correct @Pooja.
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