Civil Engineering - Surveying - Discussion
Discussion Forum : Surveying - Section 2 (Q.No. 9)
9.
For a curve of radius 100 m and normal chord 10 m, the Rankine's deflection angle, is
Discussion:
16 comments Page 1 of 2.
Rishabh Sharma said:
5 years ago
The ranking deflection angle = (180 x L) / 2*πR.
= 180x10 / 2x3.14x100.
= 1800/628 = 2.866.
Convert 2.866 in to degree = 2degree 51mintues 58 seconds.
= 180x10 / 2x3.14x100.
= 1800/628 = 2.866.
Convert 2.866 in to degree = 2degree 51mintues 58 seconds.
(15)
Sameer sopori said:
7 years ago
in Radian = C/2R.
in Degree = (C/2R)*(180/π).
in Minutes = (C/2R)*(180/π) * 60.
So, we need the answer in degree, = (C/2R)*(180/π).
= (10/200) * 57.273,
= 2.863 decimal,
= 2°51'.53.
in Degree = (C/2R)*(180/π).
in Minutes = (C/2R)*(180/π) * 60.
So, we need the answer in degree, = (C/2R)*(180/π).
= (10/200) * 57.273,
= 2.863 decimal,
= 2°51'.53.
(9)
Javeed said:
3 years ago
Use the formula c/2R ×180/π degrees.
Answer in decimal form 2.864°.
2° + 0.864×60minutes.
2° 51.84minutes.
2° 51 minutes .84×60seconds.
2° 51minutes 53 seconds.
2°51'53''.
Answer in decimal form 2.864°.
2° + 0.864×60minutes.
2° 51.84minutes.
2° 51 minutes .84×60seconds.
2° 51minutes 53 seconds.
2°51'53''.
(6)
Prakash said:
7 years ago
Rankines Deflection Angle=C/2R radian.
= 10/(2*100).
= 0.05 rad,
= (180*0.05)/π ,
= 2.86°.
= 10/(2*100).
= 0.05 rad,
= (180*0.05)/π ,
= 2.86°.
(3)
Niyaz anwar said:
6 years ago
Thanks all for explaining it.
(2)
Sanjay said:
4 years ago
@All.
Thanks for explaining it.
Thanks for explaining it.
(2)
AFTAB ALAM said:
10 years ago
= 1718.9 (S/R) minut.
= 1718.9 (10/100) minut.
= 171.89/60 degree.
= 2 51'53".
= 1718.9 (10/100) minut.
= 171.89/60 degree.
= 2 51'53".
(1)
Mamatamayee said:
7 years ago
Thanks for your Good explanation @Sameer.
(1)
Zayn said:
7 years ago
Calculate the length (m) tangent of a 5 ° curve, if the deflection angle is 60 °.
(1)
Sk rahman said:
1 decade ago
Deflection = (180xc)/2x3.14R.
= 180X10/2X3.14X100.
= 2dree51'.
= 180X10/2X3.14X100.
= 2dree51'.
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