Civil Engineering - Surveying - Discussion

Discussion Forum : Surveying - Section 2 (Q.No. 9)
9.
For a curve of radius 100 m and normal chord 10 m, the Rankine's deflection angle, is
0°25'.95
0°35'.95
1°25'.53
1°35'.95
2°51'.53.
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
16 comments Page 1 of 2.

Sk rahman said:   1 decade ago
Deflection = (180xc)/2x3.14R.

= 180X10/2X3.14X100.

= 2dree51'.

Kevin said:   1 decade ago
180X10/2X3.14X100 = 2.8647 degree in decimal = 2 degree 51' 53.24".

Snehangsu Bag said:   1 decade ago
How to convert radian to degree?

AFTAB ALAM said:   10 years ago
= 1718.9 (S/R) minut.

= 1718.9 (10/100) minut.

= 171.89/60 degree.

= 2 51'53".
(1)

SHIVAM KUMAR SINGH said:   9 years ago
We can also obtain this results:

(1718.9 * 10)/(60 * 100).
Thank you.

Gurkamal singh said:   8 years ago
Formula is c/2R=10/2*100=1/20rad.=1/20*(180/3.14) degrees=2 degree 51 minutes and 53 seconds.

Yogesh said:   8 years ago
Thanks @Aftab Alam.

Sameer sopori said:   7 years ago
in Radian = C/2R.
in Degree = (C/2R)*(180/π).
in Minutes = (C/2R)*(180/π) * 60.

So, we need the answer in degree, = (C/2R)*(180/π).
= (10/200) * 57.273,
= 2.863 decimal,
= 2°51'.53.
(9)

Mamatamayee said:   7 years ago
Thanks for your Good explanation @Sameer.
(1)

Vipin Yadav said:   7 years ago
How to be change decimal into degree? @Sameer.


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