Civil Engineering - Surveying - Discussion

Discussion Forum : Surveying - Section 2 (Q.No. 9)
9.
For a curve of radius 100 m and normal chord 10 m, the Rankine's deflection angle, is
0°25'.95
0°35'.95
1°25'.53
1°35'.95
2°51'.53.
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
16 comments Page 1 of 2.

Javeed said:   3 years ago
Use the formula c/2R ×180/π degrees.

Answer in decimal form 2.864°.

2° + 0.864×60minutes.
2° 51.84minutes.
2° 51 minutes .84×60seconds.
2° 51minutes 53 seconds.
2°51'53''.
(6)

Sanjay said:   4 years ago
@All.

Thanks for explaining it.
(2)

Rishabh Sharma said:   5 years ago
The ranking deflection angle = (180 x L) / 2*πR.
= 180x10 / 2x3.14x100.
= 1800/628 = 2.866.
Convert 2.866 in to degree = 2degree 51mintues 58 seconds.
(15)

Niyaz anwar said:   6 years ago
Thanks all for explaining it.
(2)

Zayn said:   7 years ago
Calculate the length (m) tangent of a 5 ° curve, if the deflection angle is 60 °.
(1)

Prakash said:   7 years ago
Rankines Deflection Angle=C/2R radian.
= 10/(2*100).
= 0.05 rad,
= (180*0.05)/π ,
= 2.86°.
(3)

Vipin Yadav said:   7 years ago
How to be change decimal into degree? @Sameer.

Mamatamayee said:   7 years ago
Thanks for your Good explanation @Sameer.
(1)

Sameer sopori said:   7 years ago
in Radian = C/2R.
in Degree = (C/2R)*(180/π).
in Minutes = (C/2R)*(180/π) * 60.

So, we need the answer in degree, = (C/2R)*(180/π).
= (10/200) * 57.273,
= 2.863 decimal,
= 2°51'.53.
(9)

Yogesh said:   8 years ago
Thanks @Aftab Alam.


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