Civil Engineering - Surveying - Discussion

Discussion Forum : Surveying - Section 8 (Q.No. 7)
7.
The radius of a simple circular curve is 300 m and length of its specified chord is 30 m. The degree of the curve is
5.73°
5.37°
3.57°
3.75°.
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
17 comments Page 1 of 2.

Madhukar@vasavicollegeofengineering said:   4 years ago
L = 2Rsin(θ/2).
Where
L= length of chord.
R= Radius of curve.
θ = Degree of curvature.
(2)

Abhesh said:   2 years ago
The degree of the curve is 5.73 degrees.
The formula for the degree of a curve is:

Code snippet;

Degree = 1720/R.
Use code with caution. Learn more
Where R is the radius of the curve.

In this case, R = 300 m, so the degree of the curve is:

Code snippet:
Degree = 1720/300 = 5.73 degrees.
(1)

Rahul N L Diwakar said:   8 years ago
@All.

Someone are directly using 1719 or 1718 but this will only work if length of chord is 30 m so use basic formula c = r sin (d/2).
(1)

Rakesh said:   7 years ago
1720/D.
= 1720/300 = 5.73.
(1)

Atanu mandal said:   7 years ago
R=1719/D or; D=1719/R,or D=1719/300=5.73°.

Revathi said:   6 years ago
Chord length formulae:

r = c / 2 sin (Dc/2).

Above formulae after values substitution answer will come.
sin (Dc) = 5.73°.

Revathi said:   6 years ago
r=180 A/π * Dc.

Another formula for arc or chord length.

Shree said:   6 years ago
Thanks for the answer.

DDM said:   7 years ago
R =1719/D is correct because we can say that the length of chord or length of arc is 30 m and finally we get D=5.73

Thirupathi said:   7 years ago
Thanks for explaining it.


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