### Discussion :: Surveying - Section 8 (Q.No.7)

Mahima Chandel said: (May 22, 2014) | |

C= 2R*sin{(1/2)*I}. Where C= length of long chord. c=30 , R=300. =>(30/600)= sin{(1/2)*I}. =>(1/20) = sin{(1/2)*I}. =>I = 2*{sin^-1(1/20)}. =>I = 5.73 Degree. |

Amol Lande said: (Nov 19, 2014) | |

R = 1718.9/D. R: Radius of curve. D: Degree of curve. D = 1718.9/R. D = 5.73°. |

Dnyanesh said: (Nov 16, 2016) | |

R = 1718.9/D. R: Radius of the curve. D: Degree of the curve. D = 1718.9/R. D = 5.73 °. |

Amit Ami Sharma said: (Dec 14, 2016) | |

1719/300 = 5.73° |

Quazi Murtaza said: (Jan 9, 2017) | |

1718.9/300 = 5.73°. |

Sayandeelp said: (Oct 10, 2017) | |

How 1718? Explain. |

Rahul N L Diwakar said: (Jan 28, 2018) | |

@All. Someone are directly using 1719 or 1718 but this will only work if length of chord is 30 m so use basic formula c = r sin (d/2). |

Dushyant Kumar said: (Aug 20, 2018) | |

1719/300 = 5.73°. |

Atanu Mandal said: (Sep 11, 2018) | |

R=1719/D or; D=1719/R,or D=1719/300=5.73°. |

Thirupathi said: (Sep 22, 2018) | |

Thanks for explaining it. |

Ddm said: (Oct 5, 2018) | |

R =1719/D is correct because we can say that the length of chord or length of arc is 30 m and finally we get D=5.73 |

Rakesh said: (Jan 1, 2019) | |

1720/D. = 1720/300 = 5.73. |

Shree said: (May 18, 2019) | |

Thanks for the answer. |

Revathi said: (Sep 18, 2019) | |

Chord length formulae: r = c / 2 sin (Dc/2). Above formulae after values substitution answer will come. sin (Dc) = 5.73°. |

Revathi said: (Sep 18, 2019) | |

r=180 A/π * Dc. Another formula for arc or chord length. |

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