Civil Engineering - Surveying - Discussion
Discussion Forum : Surveying - Section 8 (Q.No. 7)
7.
The radius of a simple circular curve is 300 m and length of its specified chord is 30 m. The degree of the curve is
Discussion:
17 comments Page 2 of 2.
MAHIMA CHANDEL said:
1 decade ago
C= 2R*sin{(1/2)*I}.
Where C= length of long chord.
c=30 , R=300.
=>(30/600)= sin{(1/2)*I}.
=>(1/20) = sin{(1/2)*I}.
=>I = 2*{sin^-1(1/20)}.
=>I = 5.73 Degree.
Where C= length of long chord.
c=30 , R=300.
=>(30/600)= sin{(1/2)*I}.
=>(1/20) = sin{(1/2)*I}.
=>I = 2*{sin^-1(1/20)}.
=>I = 5.73 Degree.
DUSHYANT KUMAR said:
7 years ago
1719/300 = 5.73°.
Sayandeelp said:
8 years ago
How 1718? Explain.
QUAZI MURTAZA said:
9 years ago
1718.9/300 = 5.73°.
Amit ami sharma said:
9 years ago
1719/300 = 5.73°
Dnyanesh said:
9 years ago
R = 1718.9/D.
R: Radius of the curve.
D: Degree of the curve.
D = 1718.9/R.
D = 5.73 °.
R: Radius of the curve.
D: Degree of the curve.
D = 1718.9/R.
D = 5.73 °.
Amol Lande said:
1 decade ago
R = 1718.9/D.
R: Radius of curve.
D: Degree of curve.
D = 1718.9/R.
D = 5.73°.
R: Radius of curve.
D: Degree of curve.
D = 1718.9/R.
D = 5.73°.
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