Civil Engineering - Surveying - Discussion

Discussion Forum : Surveying - Section 7 (Q.No. 10)
10.
If the whole circle bearing of a line is 270°, its reduced bearing is
N 90° W
S 90° W
W 90°
90° W.
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
34 comments Page 3 of 4.

Surojit said:   7 years ago
@Prudhvi.

359°= N1°W.
And 181°=S1°W.

Rohit said:   7 years ago
360-270=90.

As the 270 lies on exact quadrant line i.e 270.

So it is W only, not even in third and fourth quadrant.
Hence, option C and D are correct.

Amexo said:   7 years ago
As per my knowledge, N 90° W is the answer.

Shiv kumar said:   7 years ago
I think both A and B is the right answer.

Prudhvi said:   8 years ago
What if W.C.B is 359, what is R.B? PLease anyone answer me.
(1)

Umashanker said:   8 years ago
Answer should be options B.

Dev said:   8 years ago
Answer should be D.

MLY said:   8 years ago
I think the answer is 90° W.

Santhosh said:   8 years ago
Answer is option B. So 90 degree W.

Rakesh said:   8 years ago
Clear between w90 or 90w?


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