Civil Engineering - Surveying - Discussion
Discussion Forum : Surveying - Section 4 (Q.No. 1)
1.
The reduced bearing of a line is N 87° W. Its whole circle bearing is
Discussion:
17 comments Page 1 of 2.
Amanuel molito said:
5 years ago
It is found in the 4th quadrant because:-0-90 first quadrant,90-180 2nd quadrant,180-270 3rd, quadrant and 270-360 fond in 4th quadrant.
So, 273 is on the fourth quadrant and to find, W.C.B = 360 - 87 = 273.
So, 273 is on the fourth quadrant and to find, W.C.B = 360 - 87 = 273.
(2)
Kajiji said:
9 years ago
It is in 4th quadrant, because it is northwest. North west is at 4th quadrant and it is the clockwise direction it will be 360-87=273.
(1)
Durge said:
9 years ago
Because in WCB method all bearing are measured north direction and in this case, it is in anticlock wise so 360 - 87 = 273.
Hari said:
1 decade ago
The whole circle bearing (W.C.B) of a line is the horizontal angle measured clockwise from the North limb of the meridian.
Makvana Disha said:
10 years ago
Here, clearly given its N87°W, and North to West is 4th quadrant so the ans. is 360-87= 273.
Vyshnavi said:
1 decade ago
It is in 4 quadrant, to convert it from RB to WCB = 360-Bearing of line.
360-87 = 273.
360-87 = 273.
MUHAMMAD SALMAN said:
7 years ago
We know that,
W.C.B=360-R.B (in case of the 4th quadrant),
so,
W.C.B=360-87=273°.
W.C.B=360-R.B (in case of the 4th quadrant),
so,
W.C.B=360-87=273°.
Teja said:
1 decade ago
I think north west is in 3rd quadrant. How you say that is in 4th quadrant?
Nigam said:
7 years ago
273 is the correct answer. I agree with the given option.
(1)
Nigam said:
7 years ago
273 is the correct answer. I agree with the given option.
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