Civil Engineering - Surveying - Discussion
Discussion Forum : Surveying - Section 4 (Q.No. 1)
1.
The reduced bearing of a line is N 87° W. Its whole circle bearing is
Discussion:
17 comments Page 1 of 2.
Vyshnavi said:
1 decade ago
It is in 4 quadrant, to convert it from RB to WCB = 360-Bearing of line.
360-87 = 273.
360-87 = 273.
Sir A.P.J Abdul kalam said:
1 decade ago
How can we know that the bearing is in which quadrant?
Teja said:
1 decade ago
I think north west is in 3rd quadrant. How you say that is in 4th quadrant?
Hari said:
1 decade ago
The whole circle bearing (W.C.B) of a line is the horizontal angle measured clockwise from the North limb of the meridian.
Makvana Disha said:
10 years ago
Here, clearly given its N87°W, and North to West is 4th quadrant so the ans. is 360-87= 273.
Durge said:
9 years ago
Because in WCB method all bearing are measured north direction and in this case, it is in anticlock wise so 360 - 87 = 273.
Ben said:
9 years ago
How to know that it's anticlock wise?
Kajiji said:
9 years ago
It is in 4th quadrant, because it is northwest. North west is at 4th quadrant and it is the clockwise direction it will be 360-87=273.
(1)
Amit naik said:
8 years ago
360°-87°= 273°.
Abhishek said:
8 years ago
What if it was south east?
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