Civil Engineering - Surveying - Discussion

Discussion Forum : Surveying - Section 4 (Q.No. 1)
1.
The reduced bearing of a line is N 87° W. Its whole circle bearing is
87°
273°
93°
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
17 comments Page 1 of 2.

Amanuel molito said:   3 years ago
It is found in the 4th quadrant because:-0-90 first quadrant,90-180 2nd quadrant,180-270 3rd, quadrant and 270-360 fond in 4th quadrant.

So, 273 is on the fourth quadrant and to find, W.C.B = 360 - 87 = 273.
(1)

Alom said:   5 years ago
273 is the Right answer. I agree.
(1)

Nigam said:   6 years ago
273 is the correct answer. I agree with the given option.
(1)

Nigam said:   6 years ago
273 is the correct answer. I agree with the given option.

Nigam said:   6 years ago
273 is the correct answer. I agree with the given option.

MUHAMMAD SALMAN said:   6 years ago
We know that,

W.C.B=360-R.B (in case of the 4th quadrant),
so,
W.C.B=360-87=273°.

Messaymola said:   6 years ago
Nice explanation. Thanks.

Abhishek said:   6 years ago
What if it was south east?

Amit naik said:   6 years ago
360°-87°= 273°.

Kajiji said:   7 years ago
It is in 4th quadrant, because it is northwest. North west is at 4th quadrant and it is the clockwise direction it will be 360-87=273.
(1)


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