Civil Engineering - Surveying - Discussion
Discussion Forum : Surveying - Section 2 (Q.No. 24)
24.
A tape of length l and weight W kg/m is suspended at its ends with a pull of P kg, the sag correction is
.Discussion:
31 comments Page 2 of 4.
Gokul said:
6 years ago
W=udl.
So, W=wl,
= l*(wl)^2/24p^2.
sag correction = l^3w^2/ 24p^2.
So, W=wl,
= l*(wl)^2/24p^2.
sag correction = l^3w^2/ 24p^2.
(3)
Nitya said:
8 years ago
((wl)^2*-d)÷24P^2 so I think given answer is correct.
Baloch said:
9 years ago
I think its l^2 (not 3).
Correct me, If I am wrong.
Correct me, If I am wrong.
Vatsal said:
9 years ago
Option A is right answer.
(L/24) * (WL/P)^2.
(L/24) * (WL/P)^2.
Ganesh rajgure said:
9 years ago
As per my knowledge, it is w^2l^2/24P^2.
Bhupendra murariya said:
9 years ago
Sag correction formula (WL)^2/(24P)^2.
KAWERI kulat said:
8 years ago
I think formula is w2l2/24p2 not l3.
Navya said:
8 years ago
The correct answer is 1/24 (W/P) L.
Lohith GC said:
5 years ago
The Correct answer is W^2L/24P^2.
Kibs said:
7 years ago
Sag correction = L(W)^2/24(P)^2.
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