Civil Engineering - Surveying - Discussion
Discussion Forum : Surveying - Section 2 (Q.No. 24)
24.
A tape of length l and weight W kg/m is suspended at its ends with a pull of P kg, the sag correction is
.Discussion:
31 comments Page 2 of 4.
Nouman khan said:
7 years ago
From know source formula of sag correction is = lw^2/24p^2.
The weight here is w/m while in formula its w only thus;
SAG correction = l(w*l)^2/24p^2 ( To cancel meters of weight).
Thus option A is right.
The weight here is w/m while in formula its w only thus;
SAG correction = l(w*l)^2/24p^2 ( To cancel meters of weight).
Thus option A is right.
Pawar.ce said:
7 years ago
@All.
The Formula for correction for sag is= (w^2L^3)/24P^2.
Where w= weight of the tape in N/m.
And
w=W/L.
where W= weight of the tape in N.
Therefore above formula can also be written as;
Correction= (W^L)/24P^2.
The Formula for correction for sag is= (w^2L^3)/24P^2.
Where w= weight of the tape in N/m.
And
w=W/L.
where W= weight of the tape in N.
Therefore above formula can also be written as;
Correction= (W^L)/24P^2.
Sachin said:
7 years ago
It's is W^2l/24p^2.
Anuj kumar said:
7 years ago
It is w^2l^2/24p^2.
Jyoti Bhatia said:
7 years ago
@Kaweri and @Vishal.
You both are correct. The correct answer is w^2L^2/24P^2.
You both are correct. The correct answer is w^2L^2/24P^2.
Vishal said:
7 years ago
It is W^2l^2/24p^2.
Chandradeep said:
10 years ago
Its lw^2/24p^2.
Aitizaz Afser said:
8 years ago
L x (mg x l ) *2/ 24p*2 is original formula.
Reference book TP Kanetkar page 13.
Mg is equal to W so L*3 W*2/ 24P*2 is the answer.
Reference book TP Kanetkar page 13.
Mg is equal to W so L*3 W*2/ 24P*2 is the answer.
Harsh said:
8 years ago
A is correct.
W is udl,
W=wl.
W is udl,
W=wl.
KAWERI kulat said:
8 years ago
I think formula is w2l2/24p2 not l3.
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