Civil Engineering - Surveying - Discussion
Discussion Forum : Surveying - Section 1 (Q.No. 42)
42.
The slope correction for a length of 30 m along a gradient of 1 in 20, is
Discussion:
58 comments Page 4 of 6.
HITESH KUMAR said:
1 decade ago
Slope correction= h/2*2l.
Priya said:
1 decade ago
Can any one explain this properly?
Dash said:
1 decade ago
What is Gradient?
Ahishek said:
1 decade ago
How h = 1.5?
Anil soni said:
1 decade ago
For 20 m, h = 1 m. So for 30 m, h = 1.5 m.
Pranab said:
1 decade ago
h = 1.5 m & l = 30 m.
So that = h2/2l = (1.5)2/2*30 = 0.0375 cm.
So that = h2/2l = (1.5)2/2*30 = 0.0375 cm.
Prashant said:
1 decade ago
(H2/2L)+(H4/8L3) as gradient is 1 in 20. i.e For 20 m, h = 1 m.
So for 30 m, h = 1.5 m which is less than 3 m.
Therefore second term of equation should be neglected.
Answer is (1.5)2/2x3000 = 3.75 cm.
So for 30 m, h = 1.5 m which is less than 3 m.
Therefore second term of equation should be neglected.
Answer is (1.5)2/2x3000 = 3.75 cm.
Engr Attaullah Khan Tareen said:
1 decade ago
For 20 m, h = 1 m. So for 30 m, h = 1.5 m.
So that = h^2/2l = (1.5) 2/2*30 = 0.0375 m.
1 m = 100 cm so 0.0375*100 = 3.75 cm.
So that = h^2/2l = (1.5) 2/2*30 = 0.0375 m.
1 m = 100 cm so 0.0375*100 = 3.75 cm.
Maheshkumar said:
1 decade ago
In 1 in 20 means, 20m = 1m.
So total 30m length = 1.5m.
In Gradient 1 in 20 Means.
Imagine Triangle, length-30m & Height-1.5m.
Use Pythagoras theorem.
X2 = 302+1.52.
X = 30.0375m.
Change length = 30.0375-30.
= 0.0375m.
= 3.75cm.
So total 30m length = 1.5m.
In Gradient 1 in 20 Means.
Imagine Triangle, length-30m & Height-1.5m.
Use Pythagoras theorem.
X2 = 302+1.52.
X = 30.0375m.
Change length = 30.0375-30.
= 0.0375m.
= 3.75cm.
Kanhu said:
1 decade ago
Slope correction for a sloping ground = h^2/2l.
Where h = height.
l = length of the ground.
Where h = height.
l = length of the ground.
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