Civil Engineering - Surveying - Discussion
Discussion Forum : Surveying - Section 1 (Q.No. 42)
42.
The slope correction for a length of 30 m along a gradient of 1 in 20, is
Discussion:
58 comments Page 3 of 6.
Ritesh Kumar singh said:
6 years ago
Thanks for the explanation @Shubhajit Chakrabarty.
Sindhu said:
6 years ago
If 30m replace 60m then h=?
Sathya said:
6 years ago
@Sindhu.
It is 0.075.
It is 0.075.
Sameer sopori said:
7 years ago
h^2/2L.
h= 1.5 (because of 1:20, 1/20 * 30 = 1.5),
h= 2.25/60,
h= 0.375m,
h= 0.375 * 100,
h= 3.75cm.
h= 1.5 (because of 1:20, 1/20 * 30 = 1.5),
h= 2.25/60,
h= 0.375m,
h= 0.375 * 100,
h= 3.75cm.
Charan Singh Majhi said:
6 years ago
Slope correction = h^2/2l = 1.5^2/2*30 = 0.0375mtr = 3.75cm.
Ankit said:
6 years ago
Slope correction is negative or positive? Give details about it.
Adarsh said:
5 years ago
Slope correction is always negative.
Avinash said:
12 months ago
For Determining H = 20/30 = 1.5
The formula for slope H^2/2L.
L = 30.
1.5^2/2×30 = 0.0375 × 100 = 3.75cm.
The formula for slope H^2/2L.
L = 30.
1.5^2/2×30 = 0.0375 × 100 = 3.75cm.
Vicky said:
8 months ago
Agree, the Correct answer is 3.75.
Baloch said:
9 years ago
Slope correction = h^2 / 2l.
h = 20/30 = 1.5.
l = length.
By submitting the value you will get the answer.
h = 20/30 = 1.5.
l = length.
By submitting the value you will get the answer.
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