Civil Engineering - Surveying - Discussion
Discussion Forum : Surveying - Section 1 (Q.No. 42)
42.
The slope correction for a length of 30 m along a gradient of 1 in 20, is
Discussion:
58 comments Page 2 of 6.
Umar said:
5 years ago
For 20 m chain slope correction is 1m.
Therefore 1/20 * 30 = 1.5,
So (1.5 * 1.5)/2 * 30 = 0.0375m,
ie 0. 0.375 * 100 = 3.75.
Therefore 1/20 * 30 = 1.5,
So (1.5 * 1.5)/2 * 30 = 0.0375m,
ie 0. 0.375 * 100 = 3.75.
(1)
Avinash said:
1 year ago
For Determining H = 20/30 = 1.5
The formula for slope H^2/2L.
L = 30.
1.5^2/2×30 = 0.0375 × 100 = 3.75cm.
The formula for slope H^2/2L.
L = 30.
1.5^2/2×30 = 0.0375 × 100 = 3.75cm.
(1)
Karn chaurasiya said:
6 years ago
150/ n^2 because 30 metre chain used and now slope current is 150/ 20^2 = 150 ÷ 400 = 0.375 m or 3. 75 cm.
Mamatamayee said:
8 years ago
Thanks for the explanation.
Samadhan said:
8 years ago
The exact formula is = (L- √(L^2-h^2)) Now in words
Where L=length and h =meaning is same as above,
L=30m And h=1.5m..
Where L=length and h =meaning is same as above,
L=30m And h=1.5m..
Aditya singh said:
8 years ago
Let me clearly explain this for those who are confused.
The formula for slope correction is;
C=h^2/2L.
Now since grade is given is 1 in 20.
That means for 20 m horizontal movement there will be a movement of 1m vertical..therefore accordingly for 30 m it will30/20 =1.5m.
Now, put this into the formula and you will get 3.75 as answer.
The formula for slope correction is;
C=h^2/2L.
Now since grade is given is 1 in 20.
That means for 20 m horizontal movement there will be a movement of 1m vertical..therefore accordingly for 30 m it will30/20 =1.5m.
Now, put this into the formula and you will get 3.75 as answer.
Kiran said:
8 years ago
Thank you all for explaining the solution.
Gulshan Kumar said:
8 years ago
But 30 M is along the gradient, not horizontal distance.
So, the value of h won't be exactly 1.5 M.
So, the value of h won't be exactly 1.5 M.
Shubhajit Chakrabarty said:
7 years ago
Let me clearly explain,
tanθ = height/ base.
=> tanθ = 1/20,
=>θ = 2.86.
Now actual slop correction = l(1-cosθ).
=> 30(1-cos2.86) = 0.0373m.
=> 3.73 cm.
tanθ = height/ base.
=> tanθ = 1/20,
=>θ = 2.86.
Now actual slop correction = l(1-cosθ).
=> 30(1-cos2.86) = 0.0373m.
=> 3.73 cm.
Manoj said:
7 years ago
By using of similarity of the triangle.
H = 30÷401 and putting into slope correction formula.
H = 30÷401 and putting into slope correction formula.
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