Civil Engineering - Surveying - Discussion

Discussion Forum : Surveying - Section 1 (Q.No. 42)
42.
The slope correction for a length of 30 m along a gradient of 1 in 20, is
3.75 cm
0.375 cm
37.5 cm
2.75 cm.
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
58 comments Page 1 of 6.

Vicky said:   8 months ago
Agree, the Correct answer is 3.75.

Avinash said:   12 months ago
For Determining H = 20/30 = 1.5
The formula for slope H^2/2L.
L = 30.
1.5^2/2×30 = 0.0375 × 100 = 3.75cm.

S s bisht said:   3 years ago
Hypotenusal allowance.

Slope correction will be 75/(n^2)links (for 30 m chain) , where 1:n is the slope.
Cs = 75/(20 ^2) links,
= 0.1875 links of 30 m chain,
= 0.1875*20 (one links =20cm),
= 3.75 cm => Answer.
(3)

Jahangir Abbas Sahil said:   4 years ago
Slope Correction Formula=h^2/2l ---> (1)
Slope=1:20 =1/20 = 0.05.

h= slope * l= (1/20)(30) = 1.5m.

Now eq(1) becomes,
(1.5)^2/2(30) = 0.0375m.
1m = 100cm.
So,
0.0375(100cm) = 3.75cm.
(37)

V. Deepa said:   4 years ago
Good Explanations. Thanks.
(6)

Balochistan said:   4 years ago
h=1 in 20 or 0.5 in 10.
for l = 30 m. h=1.5.
So, that = h2/2l (slope correction formula)= (1.5)2/2*30 = 0.0375m. x 100 = 3.75cm.
(5)

Umar said:   4 years ago
For 20 m chain slope correction is 1m.
Therefore 1/20 * 30 = 1.5,
So (1.5 * 1.5)/2 * 30 = 0.0375m,
ie 0. 0.375 * 100 = 3.75.
(1)

Mir Imroz Ahmad said:   5 years ago
The correction for slope is (h)^2/2l.
h = 1/20 * 30 = 1.5.
Correction for slope = 1.5^2/2*30=.0375*100 = 3.75cm.
(7)

Lav Kumar Yadav said:   5 years ago
Slope correction =h^2/2L.
So, 1:20.
20m=1m.
1m=1/20m.
30m=1/20*30=1.5.
H= 1.5.
(1.5) ^2/2*30=0.0375m.
= 3.75 cm Answer.
(4)

Adarsh said:   5 years ago
Slope correction is always negative.


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