Civil Engineering - Surveying - Discussion
Discussion Forum : Surveying - Section 1 (Q.No. 42)
42.
The slope correction for a length of 30 m along a gradient of 1 in 20, is
Discussion:
58 comments Page 5 of 6.
Ali said:
9 years ago
We know for 30 m length, h = 1.5
And given gradient is 1 in 20 i.e 1/20
So, the equation of slope correction is,
= h^2 / 2l
= 1.5^2 / 2*30 m
= 2.25 / 60m
= 0.0375 m or 3.75 cm
And given gradient is 1 in 20 i.e 1/20
So, the equation of slope correction is,
= h^2 / 2l
= 1.5^2 / 2*30 m
= 2.25 / 60m
= 0.0375 m or 3.75 cm
Swamy said:
9 years ago
Hi, friends all give the good explanations. Thank you.
Hima Bindu said:
9 years ago
How h =1.5?
MD FAISAL said:
9 years ago
In ABC triangle,
AC = l = 30m.
Slope = 1 : 20.
1 in20 so in 30 = (1/20) * 30 = 1.5
Therefore BC = 1.5m.
And AB extends to BB'.
And meet to points A as arc & B as a straight line.
Here BB'= correction of line,
= AC - AB.
AB = (30^2 - 1.5^2)^1/2
= 29.962m.
BB' = 30 - 29.962
= 0.0375m or 3.75cm.
AC = l = 30m.
Slope = 1 : 20.
1 in20 so in 30 = (1/20) * 30 = 1.5
Therefore BC = 1.5m.
And AB extends to BB'.
And meet to points A as arc & B as a straight line.
Here BB'= correction of line,
= AC - AB.
AB = (30^2 - 1.5^2)^1/2
= 29.962m.
BB' = 30 - 29.962
= 0.0375m or 3.75cm.
Sandeep said:
1 decade ago
(1.5)2 / 2x3000 = 3.75 cm.
Note: Length 30 m, gradient 1/20 ; h= 1.5.
Equation : h2/2l.
Note: Length 30 m, gradient 1/20 ; h= 1.5.
Equation : h2/2l.
Nawa Raj Budha said:
9 years ago
Good explanations friends. Thank you.
Sanjukta said:
9 years ago
Thank you for the explanation friends.
Bhupendra murariya said:
9 years ago
Not understanding, Please give the correct explanation for this question.
Sunny Thakur said:
8 years ago
Thanks for the explanation friends.
Harsh Rathod said:
8 years ago
Thank you all for your explanation.
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