Civil Engineering - Surveying - Discussion
Discussion Forum : Surveying - Section 7 (Q.No. 24)
24.
The correction to be applied to each 30 metre chain length along θ° slope, is
Discussion:
26 comments Page 1 of 3.
Sumit said:
9 years ago
How it is possible? Explain.
Prashant said:
8 years ago
Anyone explain this answer.
Dilip said:
8 years ago
Slope correction is = L(cosθ-1).
Can you explain how this is wrong?
Can you explain how this is wrong?
Manish said:
8 years ago
The correct answer is Angle with θ l (1-cosθ).
Ajaynakum said:
8 years ago
Slope correction = L (1-cosθ).
Then A is correct answer.
Then A is correct answer.
Nikhitha said:
8 years ago
How A will be correct?
I think C is correct.
I think C is correct.
Akash said:
8 years ago
Actual slope correction is always -ve therefore, Correction = -[L(1-cosX)].
=(LcosX-L).
=L(cosX-1) ; now L is 30m chain.
So the answer comes out to be;
=30(cosX-1) m.
=(LcosX-L).
=L(cosX-1) ; now L is 30m chain.
So the answer comes out to be;
=30(cosX-1) m.
Akash said:
8 years ago
So, the correct option has to be "C"30(cosX-1)m.
JITENDRA KUMAR said:
8 years ago
We know that formula for determining.
L(1-cosθ) we also know that cosθ=1/secθ
Then
L(1-1/secθ)
L(secθ-1)
Here L=30.
Hence;
30(secθ-1).
So this is the Right answer.
L(1-cosθ) we also know that cosθ=1/secθ
Then
L(1-1/secθ)
L(secθ-1)
Here L=30.
Hence;
30(secθ-1).
So this is the Right answer.
Shailendra said:
7 years ago
@Jitendra Kumar.
Option C is correct.
Option C is correct.
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