Civil Engineering - Surveying - Discussion
Discussion Forum : Surveying - Section 7 (Q.No. 24)
24.
The correction to be applied to each 30 metre chain length along θ° slope, is
Discussion:
26 comments Page 2 of 3.
Prabil said:
7 years ago
@Jitendra Kumar
L{(secθ -1)/secθ}.
So, Option C is correct.
L{(secθ -1)/secθ}.
So, Option C is correct.
Gyan said:
7 years ago
The correction for chain length is L(secθ -1).
Kiran said:
6 years ago
Please explain it @Gyan.
Nungshi Jr said:
6 years ago
Hypotenusal allowance = chain length (secθ-1).
Nungshi Jr said:
6 years ago
Hypotenusal allowance = chain length (secθ-1).
James bond said:
6 years ago
L'=30m, l=L' cosθ.
So, (L'- l)
= L' - L' cosθ
= L'(1 - cosθ)
= 30(1-cosθ) it's answer C.
So, (L'- l)
= L' - L' cosθ
= L'(1 - cosθ)
= 30(1-cosθ) it's answer C.
Subha said:
6 years ago
What is Hypotenusal allowance @Nungshi jr.
Adnan said:
6 years ago
L(secθ-1) is correct because ;
SLOP . L(1- cos0).
1-cos0 ------ gives eq 1 eg,
Now, cos0 = 1/sce0.
= 1-1/sec0.
= sec0-1/sec0 ------ eq 2.
COMPARE eq 1, eq2.
= sec0(1-cos0)= sec0-1
= solve LHS
sec0(1-1/sec0)
We get sec0 -1.
SLOP . L(1- cos0).
1-cos0 ------ gives eq 1 eg,
Now, cos0 = 1/sce0.
= 1-1/sec0.
= sec0-1/sec0 ------ eq 2.
COMPARE eq 1, eq2.
= sec0(1-cos0)= sec0-1
= solve LHS
sec0(1-1/sec0)
We get sec0 -1.
Raaga chakradhar said:
5 years ago
Slope correction is=L(cos0-1).
But here the question is not about slope correction it is asking about hypotension allowance i,e the correction required to be applied for the given chain length for a given slope.
So, in indirect chaining hypotension allowance is=L(sec0-1).
But here the question is not about slope correction it is asking about hypotension allowance i,e the correction required to be applied for the given chain length for a given slope.
So, in indirect chaining hypotension allowance is=L(sec0-1).
Madhu said:
4 years ago
Option (A) is correct.
The question is asking about hypotenusal allowance.
I will explain. This is a bit lengthy. But since there is no option for uploading a figure, I have to type this much. So please read carefully.
For surveying the distance we need is the horizontal distance. But for sloping grounds, we can't directly measure the horizontal distance.
So we will measure the sloping distance and apply the correction (by knowing the slope). We are doing it
(i) either by measuring the full sloping distance once and applying the correction at the office later by using trigonometric relations,
(ii) or we will apply corrections at each chain length so that we don't have to do any corrections at the office. Keep in mind this much.
Here we are using the second method.
Suppose we are measuring a single chain distance L from A to B along a slope of 'theta' degree,
AB = L metre.
The TRUE horizontal distance for this AB is Lcos(theta), which will be less than L metre.
So what we do is we will mark a point B' whose TRUE length is L metre, which is ahead of actual measured point B. Then we will start the next chain from the point B' instead of B.
For that, we take Lm as the horizontal distance and find the sloping distance for that.
AB'cos (θ) = L
AB' = L /cos(θ),
AB' = L sec (θ).
Hypotenusal allowance (HA) = the distance BB' we have to mark ahead of B so that the measured length along the slope is the true horizontal distance.
HA = AB - AB'
= L.sec(θ) - L,
= L [sec (θ) - 1].
The question is asking about hypotenusal allowance.
I will explain. This is a bit lengthy. But since there is no option for uploading a figure, I have to type this much. So please read carefully.
For surveying the distance we need is the horizontal distance. But for sloping grounds, we can't directly measure the horizontal distance.
So we will measure the sloping distance and apply the correction (by knowing the slope). We are doing it
(i) either by measuring the full sloping distance once and applying the correction at the office later by using trigonometric relations,
(ii) or we will apply corrections at each chain length so that we don't have to do any corrections at the office. Keep in mind this much.
Here we are using the second method.
Suppose we are measuring a single chain distance L from A to B along a slope of 'theta' degree,
AB = L metre.
The TRUE horizontal distance for this AB is Lcos(theta), which will be less than L metre.
So what we do is we will mark a point B' whose TRUE length is L metre, which is ahead of actual measured point B. Then we will start the next chain from the point B' instead of B.
For that, we take Lm as the horizontal distance and find the sloping distance for that.
AB'cos (θ) = L
AB' = L /cos(θ),
AB' = L sec (θ).
Hypotenusal allowance (HA) = the distance BB' we have to mark ahead of B so that the measured length along the slope is the true horizontal distance.
HA = AB - AB'
= L.sec(θ) - L,
= L [sec (θ) - 1].
(3)
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