Civil Engineering - Surveying - Discussion

Discussion Forum : Surveying - Section 7 (Q.No. 24)
24.
The correction to be applied to each 30 metre chain length along θ° slope, is
30 (sec θ - 1) m
30 (sin θ - 1) m
30 (cos θ - 1) m
30 (tan θ - 1) m
30 (cot θ - 1) m.
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
26 comments Page 3 of 3.

Shubham said:   4 years ago
We know that slope correction is L(1-cosθ) and this is only correct..If you take sec then where that denominator will go then? Please anyone explain me.
(1)

Ashish said:   4 years ago
@Madhu.

I agree with your answer. Great thanks.

Tofik said:   4 years ago
@Madhu.

AB not equal L it Lcosθ.

Vijay vj said:   3 years ago
l is slope length and D is the horizontal distance and θ angle of slope.

Now the error is;
L-D.
L-Lcos(θ)
L(1-cos(θ)) this is error always positive.
Correction = - error.
= - [L (1-cos(θ)].
= L[cos(θ) -1].

This is my answer.
(2)

Shubham Kumar said:   3 years ago
Hypotensual correction: L(secθ-1).
Slope correction: L(cosθ-1).

Thank you!
(1)

Emtiaz Ahammed said:   3 years ago
@All
Correction along with hz line = L(cosθ-1).
Correction along with slope= L(1-cosθ) or L(secθ-1).
(2)


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