Civil Engineering - Strength of Materials - Discussion

Discussion Forum : Strength of Materials - Section 4 (Q.No. 4)
4.
A rectangular log of wood is floating in water with a load of 100 N at its centre. The maximum shear force in the wooden log is
50 N at each end
50 N at the centre
100 N at the centre
none of these.
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
23 comments Page 1 of 3.

Prakash said:   4 years ago
Water exerts a resisting force equal to the applied point load of 100 N in the form of UDL over the whole span.

Let's say, the span is 10m long then, W=10N/M.

Now, the beam is loaded with UDL of 10N/M in an upward direction and a point load at the center.

From the SF diagram maximum shear 50N at the center.
(2)

Himanshu said:   8 years ago
Answer is B.

@All.

Here, you haven't considered the UDLof water which is 100/ total length. And the question of shear centre does not arise.

Anant said:   7 years ago
According to given options answer should be 50 N.

But under a point load shear force is always indeterminate.

Naresh Bastakoti said:   2 years ago
Reaction from water is coming as UDL of magnitude 100/length resultant of which will be again its centre.

PRATUL SHARMA said:   8 years ago
The UDL of water will act in the opposite direction of the 100 kN. And thus the answer is 100-50 = 50.

Akscivili@n said:   8 years ago
Because the load is passed through the shear center. It's floating 100 is right and acts at center.

Gopal Chaudhary said:   3 years ago
According to me, 50 N at center is the right answer.
Because there are applied to Beyonce's force.
(1)

Anuj j said:   4 years ago
@Civise.

Because the log is floating. So forces are balancing each other. That's why.
(1)

Civise said:   4 years ago
How do guys consider the udl of water is 50? Please explain it detail.

Gmg said:   7 years ago
The answer is A, each end 50, not centre, sf of udl at centre is zero.


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